Part A: 6w + 12 = 5w + 15
Part B: 6(8) + 12 = 5(8) + 15
48 + 12 = 40 + 15
60 = 55 = Company B equals $55 which is less than $60
Part C: $5 is saved because of the amount of money.
Hope this helps :)
Answer:
60 miles
Step-by-step explanation:
Distance apart = 100
Rate of travel. :
Anthony = 12 mph
Cleopafda = 8 mph
Using the relation :
Speed = distance / time
Distance = speed * time
If they leave at the same time, travel time Can be represented as x
Anthony's distance + Cleopafda distance = total distance
12x +. 8x = 100
20x = 100
x = 5
Hence, they both traveled for 5 hours before meeting.
Distance covered by Anthony :
Speed * time
12 mph * 5h = 60 miles
Anthony must travel. For 60 miles.
The next step to complete the construction will connect the in-center to one of the sides of the triangle.
<h3>What is a circle?</h3>
It is described as a set of points, where each point is at the same distance from a fixed point (called the center of a circle)
Samuel is trying to construct the inscribed circle of a triangle.
Using the angle bisectors to find the in-center.
Where two angles bisector meets, the point called in-center.
Next step will be: connect the in-center to one of the sides of the triangle.
Thus, the next step to complete the construction will be connect the in-center to one of the sides of the triangle.
Learn more about circle here:
brainly.com/question/11833983
#SPJ1
Answer:
-2, 8/3
Step-by-step explanation:
You can consider the area to be that of a trapezoid with parallel bases f(a) and f(4), and width (4-a). The area of that trapezoid is ...
A = (1/2)(f(a) +f(4))(4 -a)
= (1/2)((3a -1) +(3·4 -1))(4 -a)
= (1/2)(3a +10)(4 -a)
We want this area to be 12, so we can substitute that value for A and solve for "a".
12 = (1/2)(3a +10)(4 -a)
24 = (3a +10)(4 -a) = -3a² +2a +40
3a² -2a -16 = 0 . . . . . . subtract the right side
(3a -8)(a +2) = 0 . . . . . factor
Values of "a" that make these factors zero are ...
a = 8/3, a = -2
The values of "a" that make the area under the curve equal to 12 are -2 and 8/3.
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<em>Alternate solution</em>
The attachment shows a solution using the numerical integration function of a graphing calculator. The area under the curve of function f(x) on the interval [a, 4] is the integral of f(x) on that interval. Perhaps confusingly, we have called that area f(a). As we have seen above, the area is a quadratic function of "a". I find it convenient to use a calculator's functions to solve problems like this where possible.
