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3 years ago

How many grams in 200 kg

Mathematics

1 answer:

k0ka [10]3 years ago

3 0

There are 200000 grams in 200 kg

1kg = 1000g

Solution:

1000*200= 200000

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You randomly choose a jelly bean from a jar. The jar contains 20 jelly beans: 4 red jelly beans, 8 yellow jelly beans, 3 green j

9966 [12]

Answer:

1/5 probability

Step-by-step explanation:

1) The total number of jelly beans is 20. This will be your denominator.

2) There are 4 red jelly beans. This is your numerator.

3) Using the numerator and denominator we have, your fraction is 4/20.

4) That can be simplified into 1/5.

6 0

3 years ago

Which score has a higher relative position, a score of 271.2 on a test for which = 240 and , or a score of 63.6 on a test for wh

Fittoniya [83]

Answer:

The score of 271.2 on a test for which xbar = 240 and s = 24 has a higher relative position than a score of 63.6 on a test for which xbar = 60 and s = 6.

Step-by-step explanation:

Standardized score, z = (x - xbar)/s

xbar = mean, s = standard deviation.

For the first test, x = 271.2, xbar = 240, s = 24

z = (271.2 - 240)/24 = 1.3

For the second test, x = 63.6, xbar = 60, s = 6

z = (63.6 - 60)/6 = 0.6

The standardized score for the first test is more than double of the second test, hence, the score from the first test has the higher relative position.

Hope this Helps!!!

3 0

3 years ago

Find f(3) 1 point Multiple choice + Graph!

lianna [129]

we know that

f(3) is the value of the function when x is equal to 3

For x=3

see in the graph

f(3)=6

see the attached figure

therefore

<u>the answer is</u>

f(3)=6

4 0

3 years ago

If 2x-4(3-x)=18, then x=_____? Can someone please help me with this problem

denis-greek [22]

Answer:

Answer is below

Step-by-step explanation:

Simplify both sides of the equation.

$2x-4(3-x)=18\\2x+(-4)(3)+(-4)(-x)=18$

DIstribute

$2x+-12+4x=18\\(2x+4x)+(-12)=18$

CLT

$6x+-12=18\\6x-12=18$

Add 12 to both sides.

$6x-12+12=18+12\\6x=30$

Divide both sides by 6.

$\frac{6x}{6} =\frac{30}{6}\\ x=5$

7 0

3 years ago

Find a 90% confidence interval for the mean of all tree ring dates from this archaeological site. (round your answers to the nea

creativ13 [48]

Given a table below which gives the years in A.D. for an archaeological excavation site using the method of tree ring dating:

$\begin{tabular}
{|c|c|c|c|c|c|c|c|c|}
1229&1292&1187&1257&1268&1316&1275& 1317&1275
\end{tabular}$

Part A:

The sample mean is given by:

$\bar{x}= \frac{1229+1292+1187+1257+1268+1316+1275+ 1317+1275}{9} \\ \\ = \frac{11416}{9} =1268$

Therefore, the sample mean is 1268.

Part B:

We calculate the sample standard deviation as follows:

$s= \frac{1}{9-1} \left(\sqrt{(1229-1268)^2+(1292-1268)^2+(1187-1268)^2+(1257-1268)^2+(1268-1268)^2+(1316-1268)^2+(1275-1268)^2+(1317-1268)^2+(1275-1268)^2}\right)\\ \\ = \frac{1}{8}\left(\sqrt{(-39)^2+24^2+(-81)^2+(-11)^2+0^2+48^2+7^2+49^2+7^2}\right)\\ \\ = \frac{1}{8}\left(\sqrt{1521+576+6561+121+2304+49+2401+49}\right)\\ \\ = \frac{1}{8}\left(\sqrt{13,582}\right)\\ \\ = \frac{1}{8}(116.54)=14.57\approx15$

Part C:

The 90% confidence interval is given by:

$90\% \ C. \ I.=1268\pm1.65\left(\frac{15}{\sqrt{9}}\right) \\ \\ =1268\pm\left(\frac{15}{3}\right)=1268\pm5 \\ \\ =(1268-5, \ 1268+5)=(1263, \ 1273)$

8 0

3 years ago