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sweet-ann [11.9K]
3 years ago
6

(y 3 - y 2 + y + 3) ÷ (y + 1) Solve using Polynomial long division please help!

Mathematics
2 answers:
zzz [600]3 years ago
5 0
<span><span> y3 </span>-<span> y2 </span>+ y + 3                                                                                                        </span><span>- divisor<span> <span>* y2</span> </span>                                                                                                    </span><span><span>y3 </span>+<span> y2                                                                                                                   </span></span><span> -<span> 2y2 </span>+ y + 3                                                                                                   </span><span>- divisor<span> <span>* -2y1                                                                                             </span></span></span><span>-<span> 2y2 </span>- 2y                                                                                                               </span><span> 3y +<span> 3
</span></span><span>- divisor<span> <span>* 3y0</span>                                                                                                        </span></span><span> 3y + 3                                                                                                                 </span>0Quotient : <span> <span>y2-2y+3</span>  </span><span>Remainder: </span><span> 0 </span>
iren2701 [21]3 years ago
3 0
The answer is y^2 -2y-1 with a remainder of 4/y+1
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A total of 360 tickets were sold for a school play. They were either adult tickets or student tickets. The number of student tic
Tema [17]

Answer:

<h2> 120 ----------adult tickets sold.</h2><h2>240 (children tickets sold)</h2>

Step-by-step explanation:

<u>a total of 360 tickets were sold for the school play. they were either adults tickets or student tickets. the number of student tickets sold was two times the number of adult tickets sold. how many adult tickets were sold?</u>

<u>Answer by chibabykalu1 (Show Source): You can put this solution on YOUR website!</u>

<u>x, </u><u>=</u><u>student tickets</u>

<u>y, </u><u>=</u><u>adult tickets</u>

-----

<h3>=> x + y = 360 --------(1)</h3><h3> x = 2y. ----------(2)</h3>

<u>exact translation of the description into a system of equations. Solve for the value of y.</u>

<u>The process can be, solve for x in terms of y, already seen as THE second equation of the system; substitute into the other equation, and solve the result for y, and compute.</u>

<h3>=> {2y} + y = 360</h3><h3>=> 2y + y = 360</h3><h3>=> 3y = 360</h3><h3>=> (3y)/3 = +360)/4</h3><h3>=> y = 120 ----------adult tickets sold.</h3><h3 />

<u>Substitute y = 120 into equation 2 </u>

<h3>=> x = 2y</h3><h3>=> x = 2(120)</h3><h3>=> x = 240 (children tickets sold)</h3>
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timofeeve [1]
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