Answer: The mean is 3780
Step-by-step explanation:
Mean is found by adding all values and dividing the sum by how many values were added.
4250+4019+3895+3739+3401+3376=22680
22680/6=3780
There is no question here
Answer:
a) x = 1225.68
b) x = 1081.76
c) 1109.28 < x < 1198.72
Step-by-step explanation:
Given:
- Th random variable X for steer weight follows a normal distribution:
X~ N( 1154 , 86 )
Find:
a) the highest 10% of the weights?
b) the lowest 20% of the weights?
c) the middle 40% of the weights?
Solution:
a)
We will compute the corresponding Z-value for highest cut off 10%:
Z @ 0.10 = 1.28
Z = (x-u) / sd
Where,
u: Mean of the distribution.
s.d: Standard deviation of the distribution.
1.28 = (x - 1154) / 86
x = 1.28*86 + 1154
x = 1225.68
b)
We will compute the corresponding Z-value for lowest cut off 20%:
-Z @ 0.20 = -0.84
Z = (x-u) / sd
-0.84 = (x - 1154) / 86
x = -0.84*86 + 1154
x = 1081.76
c)
We will compute the corresponding Z-value for middle cut off 40%:
Z @ 0.3 = -0.52
Z @ 0.7 = 0.52
[email protected] < x < [email protected]
-.52*86 + 1154 < x < 0.52*86 + 1154
1109.28 < x < 1198.72
Answer:
$2.85
Step-by-step explanation:
45.30/15.90=2.849
rounded up to the nearest hundreth would be $2.85.
If x is the first of the integers then the statement is:
(x) , (x+2) , (x+4) , (x+6)
This means that the smallest is x and the largest is x + 6
so:
3(x) + 2(x+6) = 293
3x + 2x + 12 = 293
5x = 281
x = 56.2
This gives us a none integer (decimal)
What now?
Wait remember how x started as the lowest? what if x was the highest instead?
x, x-2, x-4, x-6
so:
3(x-6) + 2(x) = 293
5x = 315
x = 62.2
This is as close as have gotten to the answer
Cant seem to get an integer.
Maybe error in the question or some bad math on my part.
