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natulia [17]
3 years ago
6

Is c=$75x an equation if not how would i turn this into an equation.

Mathematics
1 answer:
spin [16.1K]3 years ago
7 0
It is an equaiton because there is an 'equals' sign
it expresses equality
c is equal to 75 times x
it expresses equality
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A nature museum has 2008 specimens of early birds, some with 222 wings and some with 444 wings. The specimens have a total of 40
ludmilkaskok [199]

Let's assume

number of birds with 2 wings is x

number of birds with 4 wings is y

A nature museum has 2008 specimens of early birds

so,

x+y=2008

Total of wings of 2 wings bird =2x

Total of wings of 4 wings bird =4y

The specimens have a total of 4384 wings

so, we get

2x+4y=4384

we can divide both sides by 2

x+2y=2192

so, we get system of equations as

x+y=2008

x+2y=2192

we can solve for x and y

We can subtract both equations

2008-y+2y=2192

y=184

x=2008-184

x=1824

y=184,\:x=1824

so,

number of birds with 2 wings is 1824

number of birds with 4 wings is 184.............Answer



5 0
3 years ago
Reggie is planning to visit a clients office. He is taking a plane to get there, and the flight is scheduled to take five hours.
lilavasa [31]

Answer: <em> x>6</em>

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments
kramer

Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

Slope of MN= Slope of M'N'.

Slope of MM'=NN'.

\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.

7 0
1 year ago
(02.01 LC)
denis-greek [22]

Answer:

B

Step-by-step explanation:

4 0
3 years ago
18pts Solve for x. -3x + 6 = 2x - 24 <br> A) -30 <br> B) -6 <br> C) 6 <br> D) 30
Natasha2012 [34]

Answer: B

Step-by-step explanation: x = 6

8 0
3 years ago
Read 2 more answers
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