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2 years ago

A lawn sprinkler sprays water 5 ft in every direction as it rotates. What is the area of the sprinkled lawn?

Mathematics

2 answers:

Karolina [17]2 years ago

6 0

Answer:

78.57

Step-by-step explanation:

Radius is 5 feet

Area of circle is pi*r Squared

22/7*5*5

78.57 square feet

Anvisha [2.4K]2 years ago

6 0

You would used the formula A=(pi)•r^2 so A=(pi)• 2.5^2

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A set of data whose histogram is extremely skewed yields a sample mean and standard deviation of 68.5 and 12.75, respectively. W

Montano1993 [528]

any other questions or comments about this.

8 0

3 years ago

Simplify the expression 9t^2+14-17t+6t-8t^2

slamgirl [31]

Answer:

t^2 - 11t + 14

Step-by-step explanation:

Begin by grouping like terms in 9t^2+14-17t+6t-8t^2.

First we have 9t^2 - 8t^2, or 1t^2.

Next, we have -17t + 6t, or -11t.

Last, we have the constant term 14.

The expression in simplified form is t^2 - 11t + 14.

6 0

2 years ago

6k ÷ 7 = -3<br> Solve for k

fomenos

Answer:

k = -3.5

Step-by-step explanation:

6k ÷ 7 = -3

Multiply 7 to both sides

6k = -21

Divide both sides by 6

6k/6 = -21/6

k = -3.5

To check if the answer is correct or not, you can always plug in -3.5 for k in the equation.

6(-3.5) ÷ 7 = -3

-21 ÷ 7 = -3

-3 = -3

-3 equals -3 so it is correct that k = -3.5

4 0

3 years ago

Let us have four distinct collinear points $a,$ $b,$ $c,$ and $d$ on the cartesian plane. the point $c$ is such that $\dfrac{ab}

Deffense [45]

Start with a line segment connecting two points, A and B. $\dfrac{DA}{BA}=3$ means DA is 3 times longer than BA. Clearly, D cannot fall between A and B because that would mean DA is shorter than BA. So there are two possible locations where D can be placed on the line relative to A and B.

But with $\dfrac{DB}{BA}=2$ , or the fact that DB is 2 times longer than BA, we can rule out one of these positions; referring to the attachment, if we place D to the left of A, then DB would be 4 times longer than BA.

Finally, $\dfrac{AB}{CB}=\dfrac12$ , so that CB is 2 times longer than AB. Again we have two possible locations for point C (it cannot fall between A and B), but one of them forces C to occupy the same point as D. However, A, B, C, D are distinct, so C must fall to the left of A.

Now let $d$ be the length of AB. Then the length of CD in terms of $d$ is $4d$ . We have the coordinates of C and D, and the distance between them is $\sqrt{(4-0)^2+(0-4)^2}=4\sqrt2$ . So

$4d=4\sqrt2\implies d=\sqrt2$

The slope of the line through C and D is

$\dfrac{0-4}{4-0}=-1$

and so the equation of the line through these points is

$y-4=-(x-0)\implies x+y=4$

So the coordinates of A are $(x,y)=(x,4-x)$ . The distance between C and A is $d=\sqrt2$ , so we have

$\sqrt{(x-0)^2+(4-x-4)^2}=\sqrt{2x^2}=|x|\sqrt2=\sqrt2\implies|x|=1$

Since A falls to the right of C (in the $x,y$ plane, not just in the sketch), we know to take the positive value $x=1$ . Then the $y$ coordinate is $y=4-1=3$ .

All this to say that A is the point (1, 3), so

$2x+y=2+3=5$

5 0

3 years ago

You are trying to recreate flubber because you are obsessed with that movie and you thought it was the coolest. you take 70% sli

german

Let $x$ be the amount (gal) of the 40% slime solution you end up using. You want to end up with 120 gal of the 50% solution, so that you would use $120-x$ gal of the 70% solution.

You want the final solution to consist of 50% slime, or 60 gal of slime. Each gal of the 40% solution contributes 0.4 gal of slime, while each gal of the 70% solution contributes 0.7 gal of slime. This means

$0.4x+0.7(120-x)=0.5\cdot120=60$

$\implies0.4x+84-0.7x=60$

$\implies24=0.3x$

$\implies x=80$

so the answer is B.

8 0

3 years ago