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lubasha [3.4K]
4 years ago
13

How to find the area for a Isoceles triangle

Mathematics
2 answers:
Makovka662 [10]4 years ago
3 0

Answer:

Using the lengths of the sides, label the lengths of each side, the base, and the height. Then, use the equation Area = ½ base times height to find the area.

r-ruslan [8.4K]4 years ago
3 0

Answer:

Step-by-step explanation:

A=90

Base: 12

Height: 15

Solution

A=<u>b*h</u>

     2

A =<u>12·15</u> =90

       2

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What is the equation of the line that passes through the point (4, 12) and has a y-intercept of -2?
natima [27]

Answer:

The answer is D.

Step-by-step explanation:

:DDDDDDDDD

4 0
3 years ago
24 inches is 250% of what length
Alinara [238K]
The answer is:  " 9.6 inches " .
________________________________________________________
Explanation:
________________________________________________________

24 = 250/100 * x  ;

24 = 2.5 x ; 

↔  2.5 x = 24 ; 

2.5 x / 2.5 = 24/ 2.5 ; 

x = 9.6 ; 

The answer is:  " 9.6 inches <span>" .
</span>_________________________________________________________

4 0
3 years ago
Read 2 more answers
Please help asap :( This is my "Final grade" My Teacher wants a full explanation included ! on how i got the answer. )
Mrac [35]

If the whole diameter of sphere is 6 inch(means radius is 3 inch) & thickness of material is 1 inch, so the radius of the hollow part should be 2 inch (3-1=2)

The total volume of the ball will be;

= Total volume - Volume of hollow part

= 4/3πr³ - 4/3πr³

= 4/3 × 3.14 × (3)³ - 4/3×3.14×(2)³

= 4 × 3.14 × 9 - 4/3 × 3.14 × 8

= 113.04 - 33.52

= 79.52

If the density of the material is 3.25 g/in3, then the density of 79.52 inch³ should be;

= 79.52 × 3.25

= 258.44 g

Now, if there are 8 spheres in one box, the weight if box will be;

= 258.44 × 8

= 2,067.52 g

_____________________________

Ahh! Finally done with this, if you have any doubt just do ask me :)

3 0
3 years ago
Determine the mass of a solid steel ball that has a diameter of 10 cm. The density of pure steel is 8.09 g/cm3
Basile [38]

Answer:

<em>The mass of the steel ball is 4,235.9 gr</em>

Step-by-step explanation:

<u>Density</u>

The density ρ of a substance is a measure of its mass per unit volume:

\displaystyle \rho=\frac{m}{V}

If the density and the volume are given, the mass can be calculated by solving the above formula for m:

m=\rho.V

We know the density of pure steel ρ=8.09 gr/cm3 and the diameter of a solid steel ball d=10 cm.

We need to calculate the volume of the sphere:

The volume of a sphere of radius r is given by:

\displaystyle V=\frac{4}{3}\cdot \pi\cdot r^3

The radius is half the diameter: r= 10/2 = 5 cm. Thus:

\displaystyle V=\frac{4}{3}\cdot \pi\cdot 5^3

Calculating:

V=523.6\ cm^3

The mass is:

m=8.09 gr/cm^3 \cdot 523.6\ cm^3

m=4,235.9 gr

The mass of the steel ball is 4,235.9 gr

4 0
3 years ago
What is the slope of the line that passes through (1,4) and (1,-3)
svetlana [45]
Slope = (y2 - y1)/(x2 - x1)
slope = (-3 -4)/(1 - 1)
slope -7/0
This is an undefined slope because the denominator is 0.
This would be a vertical line.
7 0
3 years ago
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