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Gnesinka [82]
4 years ago
12

It's math again! Please help!

Mathematics
1 answer:
seraphim [82]4 years ago
7 0
4. 4x^{3}-6 x^{2}+9

5. -2x^3+2x^2+9x
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Can someone help me please
Sunny_sXe [5.5K]
11. x = 10, so DCE is 72. You get the measurement of x by adding 7x + 2 and x + 8 to equal 90. When you get x, you plug it in to the equation for DCE.

12. x = 17. KNM is 131. Get the measurement of x by adding both equations again, this time equaling it to 180 since it is a straight line and doesn't have a right angle. Plug in the x to the equation for KNM. 
8 0
3 years ago
An open top box is formed by cutting squares out of a 5 inch by 7 inch piece of paper and then folding up the sides. The volume
Radda [10]

Answer:

V(x) = 4x^3  - 24x^2+35x

Step-by-step explanation:

Given

V(x) = (7 - 2x)(5 - 2x)(x)

Required

Expand the expression

V(x) = (7 - 2x)(5 - 2x)x

Expand bracket

V(x) = (7 - 2x)(5 * x - 2x * x)

V(x) = (7 - 2x)(5x - 2x^2)

Further expand bracket

V(x) = 7(5x - 2x^2) - 2x(5x - 2x^2)

V(x) = 35x - 14x^2 - 10x^2 + 4x^3

V(x) = 35x - 24x^2 + 4x^3

V(x) = 4x^3  - 24x^2+35x

7 0
3 years ago
Write a function rule based on the table below.
Mekhanik [1.2K]
To find a function that represents these values, just substitute x-values in and look for a function that gives you the correct f(x).

A) This works for 0, but not 2
B) This works for 0, 2, and 4 making it the right answer.
6 0
4 years ago
A wheel has a diameter of 28 inches. What is the approximate distance around the outside of the wheel? Use 3. 14 for pi
KonstantinChe [14]

Answer:

87.92

In this case we're trying to find circumference

Formula: c = pi×d

The problem says to use 3.14 for pi

c = 3.14 × 28 = 87.92

3 0
3 years ago
I need math help. If youre solving a geometric sequence, the equation needed is An=A1Rn-1. If A1= 5 and R= -2. My question was "
CaHeK987 [17]

Answer:

Step-by-step explanation:

an = a1 * r^(n - 1)

a1 = first term = 5

r = -2

n = nth term of the sequence

so it starts with 5

second term is :

an = a1 * r^(n - 1)......for second term

a2 = 5 * -2^(2 - 1) =

a2 = 5 * -2^1

a2 = 5 * -2

a2 = -10

an = a1 * r^(n - 1)....looking for a3

a3 = 5 * -2^(3 - 1)

a3 = 5 * -2^2

a3 = 5 * 4

a3 = 20

an = a1 * r^(n - 1)....looking for a4

a4 = 5 * -2^(4 - 1)

a4 = 5 * -2^3

a4 = 5 * -8

a4 = - 40

an = a1 * r^(n - 1)...looking for a5

a5 = 5 * -2^(5 - 1)

a5 = 5 * -2^4

a5 = 5 * 16

a5 = 80

an = a1 * r^(n-1)...looking for a6

a6 = 5 * -2^(6 - 1)

a6 = 5 * -2^5

a6 = 5 * -32

a6 = -160

4 0
3 years ago
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