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Aleks [24]
3 years ago
15

(a) Assuming that the loss distribution is t, find the parametric estimate of VaR(0.025, 24 h). (b) Find the nonparametric estim

ate of VaR(0.025, 24 h). (c) Use a t-plot to decide if the normality assumption is reasonable
Mathematics
1 answer:
GrogVix [38]3 years ago
5 0

Answer:

5

Step-by-step explanation:

Idk

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murzikaleks [220]
20mps. Because velocity is the speed per unit. In this case it is going 20 m per second
5 0
3 years ago
WHAT TWO EQAUL NUMBERS ADD TO THE EVEN NUMER 40
Mars2501 [29]

Answer:

20

Step-by-step explanation:

20+20=40

7 0
2 years ago
A rectangular garden must have a perimeter of 150 feet and an area of at least 1200 square feet. Describe the possible lengths o
kipiarov [429]

Answer: 51.86 and 23.14

Step-by-step explanation:

The rectangular garden must have a perimeter of 150 feet

Perimeter of rectangular garden =

2l + 2w=150 -----------1

The rectangular garden must have a perimeter of 150 feet and an area of at least 1200 square feet.

Area of rectangular garden =

l×w= 1200 feet^2 -----------2

From equation 2, l=1200/w

Put l=1200/w in equation 1

2× 1200/w + 2w = 150

(2400/w) +2w = 150

(2400+2w^2)/w =150

2400+2w^2= 150w

2w^2- 150w+2400=0

Using the general formula

w = [-b+-√(b^2-4ac)]/2a

a = 2, b =-150, c=2400

w =[--150+/-√(-150^2-4×2×2400)]/2×2

=[150+/-√(22500-19200)]/4

=[150+/-√3300)]/4

=(150+57.45)/4 or (150-57.45)/4

w= 207.45/4 or 92.55/4

w= 51.86 or w= 23.14

l = 1200/51.86 or l= 1200/23.14

l = 23.14. or l= 51.86

For an area of at least 1200ft^2

The dimensions are 51.86 and 23.14

4 0
3 years ago
A circle in the xy plane has a center at (3/4, 1/2)
Leokris [45]

Answer:

(x - 3/4)^2 + (y - 1/2)^2 = r^2

<em>Brainliest, please!</em>

Step-by-step explanation:

Equation of a circle: (x - h)^2 + (y - k)^2 = r^2

(x - 3/4)^2 + (y - 1/2)^2 = r^2

We do not have enough information to find the radius. Were you given another point that lies on the circle?

3 0
3 years ago
Please help!!! Which equation is in point-slope form and is depicted by the line in this graph?
Blizzard [7]
Y-y1=m(x-x1)
a point on the line is (x1,y1) and the slope is m

so
slope between (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)
so

points (-2,3) and (3,0)
slope is (0-3)/(3-(-2))=-3/(3+2)=-3/5
a point is (3,0) Or (-2,3)

so it could be
y-0=-3/5(x-3) or y-3=-3/5(x-(-2)) which is equal to y-3=-3/5(x+2)
that's the answer
B is answer
7 0
3 years ago
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