1. Find the H.C.F. of 4x2y3 and 6xy2z.
Solution:
The H.C.F. of numerical coefficients = The H.C.F. of 4 and 6.
Since, 4 = 2 × 2 = 22 and 6 = 2 × 3 = 21 × 31
Therefore, the H.C.F. of 4 and 6 is 2
18+30=48
48+40=88
88+40=128
128+50=178
Thats all i found so far in the pattern
30,40,40,50
then it drops
by 140 then adds by 30..
I dont know how else to explain it
Answer:
Step-by-step explanation:
You put a fraction in one slot, then you know you put it in another and yeah, like
1/2 To 2 then
1. To. 4
