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likoan [24]
4 years ago
15

What is 9w^0 i don't know what it is.

Mathematics
2 answers:
Valentin [98]4 years ago
6 0

9 is the correct answer. First you had to used their apply rule, and it gave us, w^0=1, or 9*1=9. Then you multiply by the numbers, and it gave us the answer is <u><em>9 is the right answer.</em></u>  Hope this helps! And thank you for posting your question at here on brainly, and have a great day. -Charlie

Ierofanga [76]4 years ago
3 0

Simplifying

9w = 0

Solving

9w = 0

Solving for variable 'w'.

Move all terms containing w to the left, all other terms to the right.

Divide each side by '9'.

w = 0

Simplifying

w = 0

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Square root of 5 rounded to the nearest tenth
Korolek [52]
The square root of 5 is 2
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4 years ago
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Consider the first four terms of the sequence below. -3, -12, -48, -192, . . . What is the 8th term of this sequence? A. -49,152
kolbaska11 [484]

Answer:

A

Step-by-step explanation:

there is a common ratio between consecutive terms , that is

- 12 ÷ - 3 = - 48 ÷ - 12 = - 192 ÷ - 48 = 4

this indicates the sequence is geometric with nth term

a_{n} = a₁ r^{n-1}

where a₁ is the first term and r the common ratio

here a₁ = - 3 and r = 4 , then

a₈ = - 3 × 4^{7} = - 3 × 16,384 = - 49,152

7 0
2 years ago
Plss show the work<br> –4z + 8 = –2z
IceJOKER [234]

Answer:

z=-4/3

Step-by-step explanation:

8=-6z

z=-8/6

z=-4/3

4 0
3 years ago
A junk box in your room contains fourteen old​ batteries, seven of which are totally dead. You start picking batteries one at a
MrMuchimi

Answer:

A junk box in your room contains fourteen old​ batteries, seven of which are totally dead.

So, number of good batteries = 14-7=7

a) The first two you choose are both good. ​

There is a 7/14 chance that we will pick a good battery.

Now there are 13 batteries left and out of that there are only 6 good ones remaining, so this becomes 6/13.

So, combined probability is = \frac{7}{14}\times \frac{6}{13}

= 0.23

b) At least one of the first three works.

\frac{7}{14} \times \frac{6}{13} \times \frac{5}{12} =0.096

And at least one is good battery, we get : 1-0.096=0.904

​c) The first four you pick all work.

There is a probability of 7/14 for the first one to work, 6/13 for the second, 5/12 for the third and 4/11 when the fourth is good, combined we get by multiplying all:

\frac{7}{14}\times \frac{6}{13}\times \frac{5}{12}\times \frac{4}{11}=0.0344

d) You have to pick five batteries to find one that works.

This condition means that we pick 4 bad batteries and 1 good battery.

The probability of picking 4 bad batteries is -

\frac{7}{14}\times \frac{6}{13}\times \frac{5}{12}\times \frac{4}{11}=0.0344

Since there are 7 good batteries remaining in 10 batteries so we will multiply 7/10 in 0.0344 to know the fifth one that finally works.  

This becomes = 0.0344\times0.7=0.024

5 0
3 years ago
Help me with this one
uranmaximum [27]

This is the answer of your question

7 0
3 years ago
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