3 years ago

How many terms are in the following expression?

Mathematics

1 answer:

Stels [109]3 years ago

4 0

There are 4 terms in the expression.

You might be interested in

Can you help please?

lina2011 [118]

-5/2

an example of how to write it is :)

5 0

2 years ago

Read 2 more answers

Can someone please help me with this

hammer [34]

It is 146 because it is equal to the other large angle.

3 0

3 years ago

Read 2 more answers

When graphing a linear inequality, what does a dashed boundary line indicate?

VLD [36.1K]

The dashed boundary line means that the solutions are not on the boundary line. It is used for < and >

8 0

2 years ago

The travel-to-work time for residents in Ventura County is unknown. Assume the population variance is 39. How large should a sam

katen-ka-za [31]

Answer:

A sample size of 128 is needed.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.93}{2} = 0.035$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.035 = 0.965$ , so $z = 1.81$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population(square root of the variance) and n is the size of the sample.

How large should a sample be if the margin of error is 1 minute for a 93% confidence interval

We need a sample size of n, which is found when $M = 1$ . We have that $\sigma = \sqrt{39}$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$1 = 1.81*\frac{\sqrt{39}}{\sqrt{n}}$

$\sqrt{n} = 1.81\sqrt{39}$

$(\sqrt{n})^2 = (1.81\sqrt{39})^2$

$n = 127.8$

Rounding up

A sample size of 128 is needed.

7 0

2 years ago

If f(x)=7x and g(x)=6x-3,find (f*g)(x)

Dovator [93]

$(f\cdot g)(x)=f(x)\cdot g(x)\\\\
(f\cdot g)(x)=7x(6x-3)=42x^2-21x
$

7 0

3 years ago