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NeTakaya
4 years ago
8

How do you figure this out?

Mathematics
2 answers:
podryga [215]4 years ago
8 0

2x^2-4x-6=0\\ x^2-2x-3=0\\ x^2+x-3x-3=0\\ x(x+1)-3(x+1)=0\\ (x-3)(x+1)=0\\ x=3 \vee x=-1

Zarrin [17]4 years ago
5 0

a b c are coefficients you look at the number that s in front of the x

a=2

b=-4

c=-6


Δ=b²-4ac= 16-4*2*(-6)=64 then x1,x2=-b+-√Δ/2a=4+-8/2*2=

x1=3

x2=-1 for those numbers the function is 0

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svetoff [14.1K]
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I'm 90% sure that the answer is: <em>5</em>

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i cant see the picture

Step-by-step explanation:

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