Question

How do you figure this out?

Answer 1

$2x^2-4x-6=0\\ x^2-2x-3=0\\ x^2+x-3x-3=0\\ x(x+1)-3(x+1)=0\\ (x-3)(x+1)=0\\ x=3 \vee x=-1$

Answer 2

a b c are coefficients you look at the number that s in front of the x

a=2

b=-4

c=-6

Δ=b²-4ac= 16-4*2*(-6)=64 then x1,x2=-b+-√Δ/2a=4+-8/2*2=

x1=3

x2=-1 for those numbers the function is 0