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melamori03 [73]
3 years ago
7

Fred has $125. He owes his mom $12 and his brother $9. what percentage of his money is owed​

Mathematics
2 answers:
lozanna [386]3 years ago
4 0

Answer: 16.8%

Convert fraction (ratio) 21 / 125 Answer: 16.8%

Step-by-step explanation:

Sphinxa [80]3 years ago
3 0

Your answer is 16.8%.

To walk it through, we’ll need to find out how much money Fred owes in total by adding the $12 he owes to his mom and the $9 he owes to his brother.

12 + 9 = 21

We can write our current numbers as a fraction representing the amount of money he owes / the amount of money he has in total.

21/125

From there, we’ll divide to find the decimal.

21/125 = .0168

And lastly, we’ll convert our decimal to a percentage!

16.8%

Therefore, Fred owes 16.8% of his money.

Hope this helps!

:)

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6n-10=4n+6 I need to value the n
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HURRY PLEASE WILL GIVE BRAINLIEST
BigorU [14]

Answer:

graph c

Step-by-step explanation:

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4 years ago
Use the laplace transform to solve the given initial-value problem. y' 5y = e4t, y(0) = 2
Basile [38]

The Laplace transform of the given initial-value problem

y' 5y = e^{4t}, y(0) = 2 is  mathematically given as

y(t)=\frac{1}{9} e^{4 t}+\frac{17}{9} e^{-5 t}

<h3>What is the Laplace transform of the given initial-value problem? y' 5y = e4t, y(0) = 2?</h3>

Generally, the equation for the problem is  mathematically given as

&\text { Sol:- } \quad y^{\prime}+s y=e^{4 t}, y(0)=2 \\\\&\text { Taking Laplace transform of (1) } \\\\&\quad L\left[y^{\prime}+5 y\right]=\left[\left[e^{4 t}\right]\right. \\\\&\Rightarrow \quad L\left[y^{\prime}\right]+5 L[y]=\frac{1}{s-4} \\\\&\Rightarrow \quad s y(s)-y(0)+5 y(s)=\frac{1}{s-4} \\\\&\Rightarrow \quad(s+5) y(s)=\frac{1}{s-4}+2 \\\\&\Rightarrow \quad y(s)=\frac{1}{s+5}\left[\frac{1}{s-4}+2\right]=\frac{2 s-7}{(s+5)(s-4)}\end{aligned}

\begin{aligned}&\text { Let } \frac{2 s-7}{(s+5)(s-4)}=\frac{a_{0}}{s-4}+\frac{a_{1}}{s+5} \\&\Rightarrow 2 s-7=a_{0}(s+s)+a_{1}(s-4)\end{aligned}

put $s=-s \Rightarrow a_{1}=\frac{17}{9}$

\begin{aligned}\text { put } s &=4 \Rightarrow a_{0}=\frac{1}{9} \\\Rightarrow \quad y(s) &=\frac{1}{9(s-4)}+\frac{17}{9(s+s)}\end{aligned}

In conclusion, Taking inverse Laplace tranoform

L^{-1}[y(s)]=\frac{1}{9} L^{-1}\left[\frac{1}{s-4}\right]+\frac{17}{9} L^{-1}\left[\frac{1}{s+5}\right]$ \\\\

y(t)=\frac{1}{9} e^{4 t}+\frac{17}{9} e^{-5 t}

Read more about Laplace tranoform

brainly.com/question/14487937

#SPJ4

6 0
2 years ago
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