Which statements about the box plot are correct? Check all that apply. Fifty percent of the data values lies between 34 and 46.
Seventy-five percent of the data values lies between 42 and 70. It is unlikely that there are any outliers. The interquartile range'is 24. The range is 36
2 answers:
Answer:
Option 1 and 3 are correct which indicate that fifty percent of the data values lie between 34 and 46, and it is unlikely there are any outliers.
Step-by-step explanation:
As the plot is not given, by an online search, same question is found online for which the plot is given as attached herewith.
From the box plot:
median=46
Q1=42
Q3=70
Q3-Q1= IQR=70-42=28
max=76
min=34
Range=max-min=76-34=42
no outliers seen from boxplot
only (1)and (3)are correct.
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Answer:
200.96 units
Step-by-step explanation:
Use the formula for the volume of a cone
Plug in the values (=3.14) and multiply them all out
Answer:
98% confidence interval for the difference μX−μY = [ 0.697 , 7.303 ] .
Step-by-step explanation:
We are give the data of Measurements of the sodium content in samples of two brands of chocolate bar (in grams) below;
Brand A : 34.36, 31.26, 37.36, 28.52, 33.14, 32.74, 34.34, 34.33, 29.95
Brand B : 41.08, 38.22, 39.59, 38.82, 36.24, 37.73, 35.03, 39.22, 34.13, 34.33, 34.98, 29.64, 40.60
Also, represent the population mean for Brand B and let
represent the population mean for Brand A.
Since, we know nothing about the population standard deviation so the pivotal quantity used here for finding confidence interval is;
P.Q. = ~
where, = Sample mean for Brand B data = 36.9
= Sample mean for Brand A data = 32.9
= Sample size for Brand B data = 13
= Sample size for Brand A data = 9
=
= 3.013
Here, and
are sample variance of Brand B and Brand A data respectively.
So, 98% confidence interval for the difference μX−μY is given by;
P(-2.528 < < 2.528) = 0.98
P(-2.528 < < 2.528) = 0.98
P(-2.528 * <
< 2.528 *
) = 0.98
P( (Xbar - Ybar) - 2.528 * <
< (Xbar - Ybar) + 2.528 *
) = 0.98
98% Confidence interval for μX−μY =
[ (Xbar - Ybar) - 2.528 * , (Xbar - Ybar) + 2.528 *
]
[ ,
]
[ 0.697 , 7.303 ]
Therefore, 98% confidence interval for the difference μX−μY is [ 0.697 , 7.303 ] .