The answer is C.379---------
Answer:
E
Step-by-step explanation:
A. x/yx * zy/yx = 2/x
B. x/y + y/z = (xz+y^2)/yz
C. x*z/z*x = 1
D. (x+y)/(y+z) = y(x+1)/y(1+z) = x+1/1+z
E. x/y / z/y = x/y * y/z = x/z
Answer:
1st and 3rd and 5th
Step-by-step explanation:
One way to solve this is to use Pythagorean theorem: the square of one leg of triangle plus square of other leg of the triangle equals c the hypotenuse (longest side of triangle). You might see this as the formula a^2 + b^2 = c^2, where a and b are the legs and c is the hypotenuse.
In this case, the legs are 3√2 and the hypotenuse is h.
Using the formula:
(3√2)² + (3√2)² = h²
18 + 18 = h²
h = 6
The other way to do this is with trigonometric angles.
Remember cosine is adjacent over hypotenuse.
cos(45°) = (3√2) / h
h = (3√2) / cos(45°)
h = 6