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S_A_V [24]
3 years ago
5

Answer as quickly as possible​

Mathematics
1 answer:
Elanso [62]3 years ago
4 0

Answer:

Solution given:

2:centroid=\frac{x_1+x_2+x_3}{3},\frac{y_1+y_2+y_3}{3}

=\frac{1+3+5}{3},\frac{2+7+3}{3}=(3,4)

4:

Slope:\frac{y_2-y_1}{x_2-x_1}=\frac{6-2}{5-3}=2

3;

perpendicular distance =\frac{ax_1+by_1+c}{\sqrt{a²+b²}}

(x_1,y_1)=(3,-2)

4x-3y+2=0

comparing above equation with ax+by+c =0 ,we get

a=4

b=-3

c=2

d=\frac{4*3+(-3*-2)+2}{\sqrt{4²+(-3)²}}

=4 units

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Which of the inequalities is true (-4<-5), (3<-2), (0<-4) (1<-2)
NikAS [45]

Answer:

(-4<-5) because in integer o is greater than all negative figures

Step-by-step explanation:

(-4<-5)

3 0
3 years ago
What’s the answer????
BARSIC [14]

Answer:

52

Step-by-step explanation:

You can solve this by dividing the shape into three rectangles.  The horizontal rectangles have the same dimensions (11 x 2).  The vertical rectangle has the dimensions of (8 x 1).  

You can determine the dimensions by the numbers given.  11 yards as the length for the hor. rectangles are given.  2 yards as the width for the hor. rectangles are also given.  For the ver. rectangles, we can determine that the width is 1 by the bottom rectangle.  The bottom rectangle shows that the length of the parts that are not connected.  We know the total length is 11.  11 - 10 = 1.  8 yards is given.

Now use the area equation for rectangles A = lw.

For the two hor. rectangles: A = (11)(2) = 22*2 = 44 yd²

For the ver. rectangle: A = lw = (8)(1) = 8 yd²

Total area = 44 + 8 = 52 yd²

5 0
3 years ago
After just 4 tenths of a 2.5-mile race was completed, Lenox took the lead and remained there until the end of the race.
mixer [17]

Answer:

Lenox lead the race is = 1.5 miles

Reid run without a cramp = 1.75 miles

Step-by-step explanation:

given data

Lenox lead race = \frac{4}{10}

total race = 2.5 mile = \frac{25}{10}

cramp = \frac{3}{10}

to find out

How many miles did Lenox lead the race and How many miles did Reid run without a cramp

solution

we know Lenox lead = \frac{4}{10}  and total race is 2.5 mile

so

Lenox lead the race is = \frac{4}{10}  of 2.5 mile

Lenox lead the race is = \frac{4}{10} × \frac{25}{10}

Lenox lead the race is = \frac{15}{10} = 1.5 miles

and

we know developed a cramp with  \frac{3}{10} of the race remaining

so

without cramp race is 1 - \frac{3}{10} = \frac{7}{10}

and run without cramp is \frac{7}{10} of 2.5 mile

Reid run without a cramp =  \frac{7}{10} × \frac{25}{10}

Reid run without a cramp =  \frac{175}{100}

Reid run without a cramp = 1.75 miles

7 0
3 years ago
Brandon wants to use the Distributive Property to figure this problem out. What should be his next step?
Scilla [17]

(8x10)+ (8x7)

This is the right answer because you need to distribute 8 on to each number

3 0
3 years ago
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try doing pythagoras theory of a×a+b×b=c×c

3 0
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