The probability that the train will be there when Alex arrives is 5/18
If Alex arrives at any time after 1.20pm the chances that train will be there is 1/3.
However if alex arrives at 1.00pm exactly there is no chance the train will be arrive there.
The probability that the train will be there increase linearly to 1/3 as alex's arrival time moves from 1.00pm to 1.20pm.
By arranging the probabilities over the first 20 minutes to get a 1/6 chance the train will be there if alex arrives between 1.00pm to 1.20pm
we get the final answer by
=1/3( 1/6 + 1/3 + 1/3)
=5/18
So, the probability that the train will be there when Alex arrives is 5/18
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So the equation you'll use is (18,000 × .041)y+18000. Y is your years which is 20. So all you need to do is plug it in to get (18,000 × .041)20+18000 and when solved is 32,760 downloads by 2030
Well idk what the numbers are, but the formula to find the are is 3.14(pi) x r^2
So, Our final answer is 145%
Answer: (1500.66,1599.34)
Step-by-step explanation:
Confidence interval for population mean:
,where 
= Sample mean , n= Sample size, z* = critical two tailed z-value , 
= population standard deviation.
As per given , we have
n= 16
square feet
square feet
Critical z-value = 
Confidence interval for population mean:
Required confidence interval: (1500.66,1599.34)
