The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is 
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:

where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:

Hence, the half life of the sample of phosphorus-32 is 
Ten and seventy-three hundredths
Answer:
thx i see there everywhere
Step-by-step explanation:
We can solve for x by raising both sides to the -3 power (which is the reciprocal of -1/3):
(c^-1/3)^-3 = x^-3
c^1=x^-3
c=x^-3
Since the exponent on the x is a negative, we have to move it to the denominator to make it positive:
c= 1/x³
3 cm because the radius is 1.5 cm and the diameter is the radius times 2