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Misha Larkins [42]
3 years ago
7

What is this answer 31,398 ÷ 65 =

Mathematics
2 answers:
iren2701 [21]3 years ago
4 0

Answer:

483.046153846

Step-by-step explanation:

goldenfox [79]3 years ago
3 0
Your answer should be 31398/65 or 483.04615384...
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What is 2.714285714285714 as a fraction?
JulijaS [17]
<span> 2  357142857/500000000</span>
5 0
4 years ago
The midpoint of UV is (5, -10). The coordinates of one endpoint are U(3,6). Find the coordinates of endpoint V.
Salsk061 [2.6K]
The coordinates of the midpoint of a line segment joining two points (x₁,y₁) and (x₂, y₂) is given by
[(x₁+x₂)/2, (y₁+y₂)/2].

Given:
(x₁,y₁) = (3,6)  for the point U.

For the midpoint,
(x₁+x₂)/2 = 5   or x₁ + x₂ = 10
(y₁+y₂)/2 = -10 or  y₁ + y₂ = -20

Therefore, the coordinates of V are
3 + x₂ = 10     =>  x₂ = 7
6 + y₂ = -20  =>   y₂ = -26

Answer:  V (7, -26)
3 0
3 years ago
Helpppppppppppppppppppppppp
Vaselesa [24]
The first thing to is factor the denominator of the rational function:
x^{2} -2x-3 to do this we'll need to find two number whose product is -3 and its sum is -2; those numbers are 1 and -3, so:
x^{2} -2x-3=(x+1)(x-3)
Now we can rewrite our rational function as follows:
f(x)= \frac{x-3}{(x+1)(x-3)}
Notice that we have a common factor (x-3) in both numerator and denominator; therefore we can cancel them:
f(x)= \frac{1}{x+1}

Taking all the above into consideration we realize that x=3 is a removable discontinuity; the correct answer is the first one: there is a hole in x=3 and asymptote  at x=-1.

4 0
3 years ago
Write the equation of the line that passes through the point (-5,5) and has a slope of -8/5
Free_Kalibri [48]

Answer:

The equation of the line that passes through the point (-5,5) and has a slope of -8/5 will be:

                                           y=-\frac{8}{5}x-3

Step-by-step explanation:

Given

  • \left(x_1,\:y_1\right)=\left(-5,5\right)
  • m=\frac{-8}{5}

Point-Slope Form equation is

\left(y-y_1\right)=m\left(x-x_1\right)

\left(y-5\right)=\frac{-8}{5}\left(x-\left(-5\right)\right)

\mathrm{Apply\:rule}\:-\left(-a\right)=a

y-5=\frac{-8}{5}\left(x+5\right)

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}

y-5=-\frac{8}{5}\left(x+5\right)

y-5+5=-\frac{8}{5}\left(x+5\right)+5

y=-\frac{8}{5}x-3

Therefore, the equation of the line that passes through the point (-5,5) and has a slope of -8/5 will be:

                                           y=-\frac{8}{5}x-3

5 0
3 years ago
Parker drew a triangle with no cogruent sides and a 95° angle. Classify the triangle by the lengths of its sides and measures of
Alika [10]
Obtuse scalene, because none of the side are equal ( which would make none of the angles equal), but the one angle is over 90°
4 0
4 years ago
Read 2 more answers
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