Answer:cost of each pound of apple= $3
And cost of each pound of orange =$2
Step-by-step explanation:
Step 1
Let cost of apples = x
And cost of Oranges =y
Let 6 pounds of apples and 3 pounds of oranges cost 24 dollars be represented as
6 x + 3y= 24----- equation 1
Also, Let 5 pounds of apples and 4 pounds of oranges cost 23 dollars be represented as
5x+ 4y= 23----- equation 2
Step 2
6 x + 3y= 24----- equation 1
5x+ 4y= 23----- equation 2
Using substitution method to solve the equation
6 x + 3y= 24
24-6x=3y
y= 24-6x/3 = 8-2x
Y= 8-2x
Substituting the value of y= 8-2x into equation 2
5x+ 4( 8-2x)= 23
5x+ 32 -8x= 23
32-23= 8x-5x
9=3x
x=9/3
x=3
Putting the value of x= 3 in equation 1 and solving to find y
6 x + 3y= 24
6(3) +3y= 24
18+3y=24
3y= 24-18
3y=6
y=6/3= 2
Therefore the cost of each pound of apple= $3
And cost of each pound of orange =$2
84/100 which would then be 42/50 which will then be 21/25
Slope=rise/run
hmm, from (0,4) to (1,1)
rise=-3
run=1
slope=-3
Answer:
C) y = 1/3x - 6
Step-by-step explanation:
y=mx+b
m=slope
b=y-intercept
1/3=m
-6=b
then plug in the numbers to get: y=1/3x - 6
Hope this helps! :)
