Unknown values can be taken as anything , for example : the most common is x for unknown values and sometimes, for angles we can take θ(theta).
it is totally upto you!
This might help explain how to do a very similar problem.... http://www.mathopenref.com/constbisectline.html
At first there are three marbles for Sam to pick from. the possibility of drawing a colored marble is 2/3. if Sam picks one of the colored marbles, the possibility of therefore (if he'd drawn the colored marble) drawing the second colored marble is 1/2. for the possibility of those happening consequently, we have to multiply the possibilities. 2/3 * 1/2 is 2/6 is 1/3. which means Sam wins in 33.333...% cases. Julie has a better chance of winning.
adding a white marble would change the possibilities to 1/2 and 1/3 consequently, meaning Sam wins in 1/2 * 1/3 = 1/6 = 16.7% cases, which is even less fair.
adding a colored marble would change the possibilities to 3/4 and 2/3 consequently, meaning Sam wins in 3/4 * 2/3 = 6/12 = 50% cases, which finally makes the game fair.
Answer:
Step-by-step explanation:
let x be the number
6+1/5x=12
1/5x=12-6
1/5x=6
x=5*6
x=30
check: 6+(1/5*30)=6+6=12
Answer:
Ooof
Step-by-step explanation:
