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rjkz [21]
3 years ago
7

Peele is interested in the average price of an entree at a French restaurant, but only has a random sample of 9 prices (prices a

re not listed on the menu). Using this random sample, Key calculates that a 90% confidence interval for the true mean is given by (65, 88). (You can assume the prices follow a normal distribution). Use this information to do the following:
a) Calculate 7. (Hint, what does a confidence interval look like?)
b) Calculate s.
c) Construct a 95% confidence interval for the true mean price of all the entrees, f.
Mathematics
1 answer:
Lisa [10]3 years ago
4 0

Answer:

Xbar = 76.5

s = 24.70

(61.19 ; 91.81)

Step-by-step explanation:

Given that :

Confidence interval = (65, 88)

Recall:

Confidence interval = xbar ± margin of error

Margin of Error = (upper boundary - lower boundary) / 2

Margin of Error = (88 - 65) /2 = 11.5

Taking the lower boundary :

Lower boundary = xbar - margin of error

xbar = lower boundary + margin of error

Xbar = 65 + 11.5

Xbar = 76.5

Margin of Error = Tcritical * s/sqrt(n)

s = sample standard deviation

Tcritical at 90% confidence, df = 9-1= 8 = 1.397

11.5 = 1.397 * s/sqrt(9)

11.5 = 1.397 * s/3

34.5 = 1.397s

s = 34.5 / 1.397

s = 24.695

s = 24.70

C.) 95% confidence interval :

Tcritical at 95%, df = 8 = 1.860

Margin of Error = 1.860 * 24.70/sqrt(9) = 15.311

Confidence interval :

Lower boundary = 76.5 - 15.311

Upper boundary = 76.5 + 15.311

(61.19 ; 91.81)

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Nina [5.8K]

Answer:

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Step-by-step explanation:

0.5 x 6 =3

3 x 5 = 15

5 0
3 years ago
If the product of a number and -8 is subtracted from the number the result is 7 more than the number find the number
Leviafan [203]

(-8x-x) 7+x I believe that's the answer

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=4x%20%2B%203y%20%3D%200%20%5C%5C5y%20%2B%2053%20%3D%2011x%20%5C%5C%20" id="TexFormula1" title=
Anvisha [2.4K]

Answer:

x = 3, y = -4

Step-by-step explanation by substitution:

Solve the following system:

{4 x + 3 y = 0 | (equation 1)

5 y + 53 = 11 x | (equation 2)

Express the system in standard form:

{4 x + 3 y = 0 | (equation 1)

-(11 x) + 5 y = -53 | (equation 2)

Swap equation 1 with equation 2:

{-(11 x) + 5 y = -53 | (equation 1)

4 x + 3 y = 0 | (equation 2)

Add 4/11 × (equation 1) to equation 2:

{-(11 x) + 5 y = -53 | (equation 1)

0 x+(53 y)/11 = -212/11 | (equation 2)

Multiply equation 2 by 11/53:

{-(11 x) + 5 y = -53 | (equation 1)

0 x+y = -4 | (equation 2)

Subtract 5 × (equation 2) from equation 1:

{-(11 x)+0 y = -33 | (equation 1)

0 x+y = -4 | (equation 2)

Divide equation 1 by -11:

{x+0 y = 3 | (equation 1)

0 x+y = -4 | (equation 2)

Collect results:

Answer: {x = 3 , y = -4

_____________________________________

Solve the following system:

{4 x + 3 y = 0

5 y + 53 = 11 x

Hint: | Choose an equation and a variable to solve for.

In the first equation, look to solve for x:

{4 x + 3 y = 0

5 y + 53 = 11 x

Hint: | Isolate terms with x to the left hand side.

Subtract 3 y from both sides:

{4 x = -3 y

5 y + 53 = 11 x

Hint: | Solve for x.

Divide both sides by 4:

{x = -(3 y)/4

5 y + 53 = 11 x

Hint: | Perform a substitution.

Substitute x = -(3 y)/4 into the second equation:

{x = -(3 y)/4

5 y + 53 = -(33 y)/4

Hint: | Choose an equation and a variable to solve for.

In the second equation, look to solve for y:

{x = -(3 y)/4

5 y + 53 = -(33 y)/4

Hint: | Isolate y to the left hand side.

Subtract 53 - (33 y)/4 from both sides:

{x = -(3 y)/4

(53 y)/4 = -53

Hint: | Solve for y.

Multiply both sides by 4/53:

{x = -(3 y)/4

y = -4

Hint: | Perform a back substitution.

Substitute y = -4 into the first equation:

Answer: {x = 3 , y = -4

7 0
3 years ago
Given a line with a slope of1/2 and a point(6,5) which lies on that find an equation to represent that line
kondor19780726 [428]

Answer:

The equation of the line is given as  2 y - x = 4.

Step-by-step explanation:

Here, the slope of the given line = 1/2

The point  on the line is (x0,y0) = (6,5)

Now, by POINT SLOPE FORMULA:

The equation of line with (x0,y0) and slope m is written as:

(y - y0) = m (x-x0)

So, here the equation of line is given as

( y- 5) = \frac{1}{2} (x-6)\\\implies 2( y-5) = ( x-6)\\or, 2y - 10 = x - 6\\\implies  2y - x = 4

Hence the equation of the line is 2 y - x = 4.

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