Answer:
71°
142°
Step-by-step explanation:
First, turn the fraction into a decimal to get a better look at the problem. To do that, divide the numerator (top half) by the denominator (bottom half). 1 divided by 3 = 0.33
0.33 is larger than 0.3. If it helps, add a 0 to 0.3 to get 0.30 and you'll see that 33 is in fact a larger number than 30. (Adding the zero does NOT change the number, it holds no place value it's just there for looks.)
Answer:
50
Step-by-step explanation:
you multiply 1/5 and 250/1 to get 250/5 then simplify to get 50
Y = -1/2x - 6......u have a slope of -1/2....u have a y int of -6 or (0,-6)
the x int can be found by subbing in 0 for y and solving for x
0 = -1/2x - 6
1/2x = -6
x = -6 * 2
x = -12.....so ur x int is -12 or (-12,0)
so go ahead and plot ur intercepts.....(0,-6) and (-12,0)...well...u cant really plot ur x axis because ur graph is not big enough....so start at (0,-6)...and I know the slope is -1/2....and u would usually start at (-12,0)...but that is not on the graph....so start at (0.-6)....and go up 1 and to the left 2, plot that point....then up 1 and to the left 2...plot that point......u would eventually cross the x axis at (-12,0).
or u could just go to desmos....its a graphing calculator...and see for urself
9514 1404 393
Answer:
A, C, B
Step-by-step explanation:
It is helpful to remember the trig identities ...
sin = 1/csc
cos = 1/sec
tan = 1/cot
__
1. sin(θ)cos(θ)sec(θ)csc(θ) = (sin(θ)csc(θ))(cos(θ)sec(θ)) = (1)(1) = 1 . . . matches A
2. 1/cot²(θ)·sec(θ)cos(θ) = 1/(1/tan²(θ))·(1) = tan²(θ) . . . matches C
3. tan(θ)/cot(θ) = tan(θ)/(1/tan(θ)) = tan²(θ) . . . matches B
