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3 years ago

Find the y-intercept for the line represented by this equation. 3y+2x=-x+5

Mathematics

1 answer:

Bond [772]3 years ago

3 0

Answer:

(0,5/3)

Step-by-step explanation:

3y+2x=-x+5

3y=-x-2x+5

3y=-3x+5

y=-x+5/3

if x=0 then y=-0+5/3=5/3

(x, y) =(0,5/3)

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Eugene noticed the temperature had dropped by 8 degrees from 17. What was the new temperature?

zubka84 [21]

Answer:

9 degrees

Step-by-step explanation:

given:

Initial temperature : 17 degrees

temperature change = reduction by 8 degrees (i.e - 8 degrees)

hence the final temperature

= initial temperature + temperature change

= 17 + (-8)

= 17 - 8

= 9 degrees

8 0

3 years ago

Which of the following functions are an example of exponential decay???

Yanka [14]

Answer:

C. II only

Step-by-step explanation:

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7 0

3 years ago

If five times the successor of a number is added to an original number the sum is 83

Alexus [3.1K]

Answer:

Let the original number be x

Successor is defined as the number which comes immediately after a particular number.

also, the successor of a whole number is the number obtained by adding 1 to that number.

Then, the successor of a number x is, x+1

As per the given condition :

we have;

$5(x+1)+x =83$

Using distributive property on LHS (i.e, $a\cdot(b+c)=a\cdot b+a\cdot c$ )

Then, we have

5x+5+x=83

Combine like terms;

6x+5=83

Subtract 5 from both the sides we get;

6x+5-5=83-5

Simplify:

6x=78

Divide both side by 6,

$\frac{6x}{6} =\frac{78}{6}$

Simplify:

x =13

Therefore, the original number x is, 13

8 0

3 years ago

Can someone explain, i'm literally sweating trying to figure it out

ASHA 777 [7]

Answer:

54 degrees.

Step-by-step explanation:

So a fun fact is that the exterior angle is equal to the sum of the opposite two interior angles (at least within triangles).

Given this, set these values equal to each other to get the value of a.

d = a + b

2a = (a+10)+44

2a = a + 54

a = 54

The measure of the exterior angle is 54 degrees.

4 0

3 years ago

Suppose $p(x)$ is a monic cubic polynomial with real coefficients such that $p(3-2i)=0$ and $p(0)=-52$. determine $p(x)$ (in exp

Maslowich

If $p(3-2i)=0,$ then complex number $3-2i$ is a root of cubic polynomial.

If polynomial has real coefficients, then conjugated $3+2i$ is also a root of polynomial.

Then the polynomial will be of a form

$p(x)=(x-(3-2i))(x-(3+2i))(x-a).$

Since $p(0)=-52,$ then

$-52=(0-(3-2i))(0-(3+2i))(0-a),\\ \\-52=(2i-3)(3+2i)a,\\ \\-52=(4i^2-9)a,\\ \\-52=(-4-9)a,\\ \\-13a=-52,\\ \\a=4.$

Therefore,

$p(x)=(x-(3-2i))(x-(3+2i))(x-4),\\ \\p(x)=(x^2-6x+13)(x-4),\\ \\p(x)=x^3-10x^2+37x-52.$

3 0

3 years ago