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3 years ago

MARKED BRAINLIEST

Mathematics

1 answer:

denis23 [38]3 years ago

4 0

Answer:

D is the answer

Step-by-step explanation:

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PLEASE HELP!!!!!!!!!!!!!

Anna35 [415]

$4y^2+2=(4y\cdot4y)+2\\
4y^2+2=16y^2+2 \leftarrow \text{not identity}\\\\
4y^2+2=(4y+y)+2\\
4y^2+2=5y+2 \leftarrow \text{not identity}\\\\
4y^2+2=4(y+y)+2\\
4y^2+2=8y+2 \leftarrow \text{not identity}\\\\
4y^2+2=4(y\cdot y)+2\\
4y^2+2=4y^2+2 \leftarrow \text{identity}$

So it's D.

8 0

3 years ago

Ratio of 6 nickels to 5 dollars

SSSSS [86.1K]

6:5. or 6/5 which ever way you choose

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3 years ago

What gas important to life was absent from earth’s earliest atmosphere?

jonny [76]

The answer would be C, oxygen because there was not a sufficient amount.

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3 years ago

Read 2 more answers

Find the absolute maximum and minimum values of f(x,y)=xy−4x in the region bounded by the x-axis and the parabola y=16−x2.

skad [1K]

Answer:

The absolute maximum and minimum is $20\; \text{and} -20.$

Step-by-step explanation:

We first check the critical points on the interior of the domain using the

first derivative test.

$f_x=y-4=0$

$f_y=x=0$

The only solution to this system of equations is the point (0, 4), which lies in the domain.

$f_{xx}=0, \;f_{yy}=0\; \text{and}\; f_{xy}=-1$

$\Rightarrow f_{xx}f_{yy}-f_{xy}=o-1=-1$

$\therefore (0,4)$ is a saddle point.

Boundary points - $(4,0), (-4,0), (0,16)$

Along boundary $y=16-x^2$

$f=x(16-x^2)-4x$

$=16x-x^3-4x$

$\Rightarrow f^'=16-3x^2-4=0$

$\Rightarrow 3x^2=12$

$\Rightarrow x=\pm2,\;\;y=14$

Values of f(x) at these points.

$\begin{array}{}(4,0)=-16\\(-4,0)=16\\(0,16)=0\\(2,14)=20\\(-2,14)=-20\end{array}$

Therefore, the absolute maximum and minimum is $20\; \text{and} -20.$

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3 years ago

Is fraction a linear equation

olya-2409 [2.1K]

Answer:

Step-by-step explanation:

We need more than two operations to solve a linear equation . If an equation contains fractions, multiply both sides of the equation by the least common denominator (LCD) to clear fractions.

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2 years ago

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MARKED BRAINLIEST