Answer:
Just so everyone knows HEY PLS DON'T JOIN THE ZOOM CALL OF A PERSON WHO'S ID IS 825 338 1513 (I'M NOT SAYING THE PASSWORD) HE IS A CHILD PREDATOR AND A PERV. HE HAS LOTS OF ACCOUNTS ON BRAINLY BUT HIS ZOOM NAME IS MYSTERIOUS MEN.. HE ASKS FOR GIRLS TO SHOW THEIR BODIES AND -------- PLEASE REPORT HIM IF YOU SEE A QUESTION LIKE THAT. WE NEED TO TAKE HIM DOWN!!! PLS COPY AND PASTE THIS TO OTHER COMMENT SECTIONS
ID- 825 338 1513 DO NOT
JOIN FOR YOUR OWN GOOD HAPPY HOLIDAYS
Step-by-step explanation:
Answer:
x< -8.125
Step-by-step explanation:
7(x+4) < 2(x-5) -3(x+9)
distribute 7, 2, -3 to the parentheses to the right
7x+28<2x-10-3x-27
add like terms
7x+28<x-37
add x to 7x and subtract -28 to -37
8x<-65
divide both sides by 8
x<-8.125 or (-65/8)
First move the terms to get
6m-m=13+2
Then collect the like terms and calculate the sum, 5m=15
Divide both sides by 5
And you get m=3
If Marcy would want to have 2 bags with the equal amount of sauce from a 9.98 pound bag of sauce, then all she needs to do is to divide the total amount of sauce, which is 9.98, by 2 bags. So if she would do this, then the equation will be 9.98/2. The answer to this problem would be 4.99 pounds of sauce per bag. This makes since because 4.99 pounds (in the first bag) + 4.99 pounds (in the second bag) will make up 9.98 pounds which is the total amount of sauce Marcy has.
Answer:
(1, 4) and (1,3), because they have the same x-value
Step-by-step explanation:
For a relation to be regarded as a function, there should be no two y-values assigned to an x-value. However, two different x-values can have the same y-values.
In the relation given in the equation, the ordered pairs (1,4) and (1,3), prevent the relation from being a function because, two y-values were assigned to the same x-value. x = 1, is having y = 4, and 3 respectively.
Therefore, the relation is not a function anymore if both ordered pairs are included.
<em>The ordered pairs which make the relation not to be a function are: "(1, 4) and (1,3), because they have the same x-value".</em>
