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Valentin [98]
3 years ago
15

53 3/4 + 12 2/3. can someone please help me

Mathematics
2 answers:
Rudik [331]3 years ago
6 0

Answer:

Exact form : 797/12

Decimal form : 66.416 (Place a line over the six in .416 to show that the six is repeating itself. It will look like this...66.41666666...)

Mixed Number form : 66 5/12

Step-by-step explanation: Convert the mixed numbers to improper fractions, then find the LCD (Least Common Denominator) and combine.

Hope this helps you out! ☺

Mumz [18]3 years ago
5 0

Answer:

66 5/12

Step-by-step explanation:

53 3/4 + 12 2/3 =

53 9/12 + 12 8/12 =

65 17/12 =

66 5/12

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Alex is 12 years older than George. Carl is Three times older than Alex The sum of their ages is 68 Find the ratio of George’s a
earnstyle [38]

Ratio of George’s age to Carl’s age to Alex’s age is 1 : 12 : 4

<em><u>Solution:</u></em>

Let "a" be the age of Alex

Let "g" be the age of George

Let "c" be the age of Carl

<em><u>Alex is 12 years older than George</u></em>

Therefore,

Age of Alex = 12 + Age of George

a = 12 + g

g = a - 12 ---- eqn 1

<em><u>Carl is Three times older than Alex</u></em>

Age of Carl = 3 x Age of Alex

c = 3a -------- eqn 2

<em><u>The sum of their ages is 68</u></em>

age of Alex + age of George + age of Carl = 68

a + g + c = 68 ----------- eqn 3

<em><u>Substitute eqn 1 and eqn 2 in eqn 3</u></em>

a + a - 12 + 3a = 68

5a - 12 = 68

5a = 12 + 68

5a = 80

a = 16

<em><u>Substitute a = 16 in eqn 2</u></em>

c = 3(16) = 48

c = 48

<em><u>Substitute a = 16 in eqn 1</u></em>

g = 16 - 12 = 4

g = 4

<em><u>Find the ratio of George’s age to Carl’s age to Alex’s age</u></em>

Ratio of George’s age to Carl’s age to Alex’s age = g : c : a

g : c : a = 4 : 48 : 16

Divide the above ratio by 4 to reduce to lowest terms

g : c : a - 1 : 12 : 4

Thus ratio of George’s age to Carl’s age to Alex’s age is 1 : 12 : 4

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