All categories

3 years ago

NEED MAJOR HELP!!!!!!!!

1 answer:

6 0

Hi,
Principal=$650, R=3.5%, T=6 yrs
Amount=Principal * (100+R%/100)^no. of yrs
Amount=650 * (100+3.5/100)^6
Amount= 650 * 103.5/100 * 103.5/100 * 103.5/100 * 103.5/100 * 103.5/100 * 103.5/100<span>
Amount=</span> 650 * 1.035 * 1.035 * 1.035 * 1.035 * 1.035 * <span> 1.035
Amount=799.016</span>
Hope this helps you.

You might be interested in

What number is being factored in this factor tree?

Hatshy [7]

Answer:

164

Step-by-step explanation:

82 multiplied by 2

8 0

3 years ago

Read 2 more answers

PLEASE HELP me!!! can give brainliest!

salantis [7]

Answer:

9 years ( approximately)

Step-by-step explanation:

900(1.03)^t = 1200

(1.03)^t= 1.33

( 1.03)^t= ( 1.03)^9

So, t= 9

5 0

3 years ago

I'm not sure about 38 - 53 please help! :)

Maru [420]

38. 6900 grams
39. 19600 grams
40. 27910 grams
41. 32840 grams
42. 610 grams
43. 970 grams
44. 3712 grams
45. 8937 grams
46. 37 grams
47. 69 grams
48. 1510 grams
49. 4700 grams
50. 150 grams
51. 15 grams
52. 15200 grams
53. 460

I'm sorry if these are wrong but I hope this could help.

5 0

3 years ago

Read 2 more answers

Identify whether the series sigma notation infinity i=1 15(4)^i-1 is a convergent or divergent geometric series and find the sum

const2013 [10]

Answer: The correct option is

(d) This is a divergent geometric series. The sum cannot be found.

Step-by-step explanation: The given infinite geometric series is

$S=\sum_{i=1}^{\infty}15(4)^{i-1}.$

We are to identify whether the given geometric series is convergent or divergent. If convergent, we are to find the sum of the series.

We have the D' Alembert's ratio test, states as follows:

Let, $\sum_{i=1}^{\infty}a_i$ is an infinite series, with complex coefficients $a_i$ and we consider the following limit:

$L=\lim_{i\rightarrow \infty}\dfrac{a_{i+1}}{a_i}.$

Then, the series will be convergent if L < 1 and divergent if L > 1.

For the given series, we have

$a_i=15(4)^{i-1},\\\\a_{i+1}=15(4)^i.$

So, the limit is given by

$L\\\\\\=\lim_{i\rightarrow \infty}\dfrac{a_{i+1}}{a_i}\\\\\\=\lim_{i\rightarrow \infty}\dfrac{15(4)^i}{15(4)^{i-1}}\\\\\\=\lim_{i\rightarrow \infty}\dfrac{15(4)^i}{15(4)^{i}4^{-1}}\\\\\\=\dfrac{1}{4^{-1}}\\\\=4>1.$

Therefore, L >1, and so the given series is divergent and hence we cannot find the sum.

Thuds, (d) is the correct option.

7 0

4 years ago

Read 2 more answers

A mailing carton in the shape of a cube has a volume of 684 cubic inches. What is the length of one side of the carton to the ne

Liula [17]

Check the picture below.

5 0

2 years ago