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tatiyna
3 years ago
6

NEED MAJOR HELP!!!!!!!!

Mathematics
1 answer:
Flura [38]3 years ago
6 0
Hi,
Principal=$650, R=3.5%, T=6 yrs
Amount=Principal * (100+R%/100)^no. of yrs
Amount=650 * (100+3.5/100)^6
Amount= 650 *  103.5/100 *  103.5/100 *  103.5/100 *  103.5/100 *  103.5/100 *  103.5/100<span>
Amount=</span> 650 *  1.035 *  1.035 *  1.035 *  1.035 *  1.035 * <span> 1.035
Amount=799.016</span>
Hope this helps you.
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I don't know how to do this. I forget plz help
Leno4ka [110]
Ok so 
0.5%=0.005
0.005x=8
x=8/0.005
x=1600
8 is 0.5% of 1600
Hope this helps
If u still don't understand plz message me
If u understand plz brainlest me
If you continue with the same formula with a different problem then you will get it correct 
Thank you!
3 0
3 years ago
Read 2 more answers
NEED HELP ASAP
VARVARA [1.3K]

When solving an equation with an absolute value term, you make two separate equations ans solve for x:

Equation 1: |4x-3|-5 = 4

1st add 5 to both sides:

|4x-3| = 9

Remove the absolute value term and make two equations:

4x-3 = 9 and 4x - 3 = -9

Solving for x you get X = 3 and x = -1.5

When you replace x with those values in the original equation the statement is true so those are two solutions.

Do the same thing for equation 2:

|2x+3| +8 = 3

Subtract 8 from both sides:

|2x+3| = -5

Remove the absolute value term and make two equations:

2x +3 = -5

2x+3 = 5

Solving for x you get -1 and 4, but when you replace x in the original equation with those values, the statement is false, so there are no solutions.

The answer is:

C. The solutions to equation 1 are x = 3, −1.5, and equation 2 has no solution.

3 0
3 years ago
Which of the following could be a slant cross section of a right cone?
andriy [413]
I believe the answer is B, Oval.
4 0
3 years ago
7
Fantom [35]

Answer:

1 sick chick FIL a have to be there by the time

8 0
1 year ago
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Which in is it.........
ANTONII [103]
I haven't done these problems in a really long time, so there's a chance that my answer might be wrong. I hypothesize that the correct answer is C. 
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