Put the numbers in order.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 2: Find the median.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 3: Place parentheses around the numbers above and below the median.
Not necessary statistically, but it makes Q1 and Q3 easier to spot.
(1, 2, 5, 6, 7), 9, (12, 15, 18, 19, 27).
Step 4: Find Q1 and Q3
Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data.
(1, 2, 5, 6, 7), 9, ( 12, 15, 18, 19, 27). Q1 = 5 and Q3 = 18.
Step 5: Subtract Q1 from Q3 to find the interquartile range.
18 – 5 = 13.
Answer:
Kindly check explanation
Step-by-step explanation:
Total Number of pens = 5
Number of defective pens = 2
Number of non-defective pens = 3
A.) number of defective pens selected :
X : {0, 1, 2}
It is possible that no defective pen will be selected ; 1 defective will be chosen or both pens are defective.
2.)
Defective as Success (since selecting a defective pen is the point of interest.
3.)
Since selection is done without replacement
Probability of success per selection is different for each selection ;
Number of defective = 2
Number of observations = 5
P(success on first selection) = 2/5
P(success on second selection) = 1/4
Hence, X is not well approximated by a binomial random variable.
4.) if selection is done with replacement ; then then the probability of success per selection will be the Same for each selection made. Hence, X will be well approximated by a binomial Random variable.
5.) If sampling is done without replacement, then the the hypergeometric function will be a more effective approximation.
Answer:
-0.0625
Step-by-step explanation:
Answer:sure I’ll be ur friend pal :)
Step-by-step explanation:
Answers:
She made ___25___ grams of ___40___% salt solution
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The given info "20 grams of 50% salt solution" tells us that we have 10 grams of pure salt
Since 50% of 20 = 0.50*20 = 10
Put another way, we have 10 grams of pure salt out of 20 total so 10/20 = 0.50 = 50% salt solution
The 20 grams of solution updates to 25 grams of solution when we add the 5 grams of water
We don't add any salt, assuming this water is fresh water
So we still have 10 grams of pure salt out of 25 grams now
10/25 = 2/5 = 0.40 = 40% is the new salt concentration
