Answer:
1 3/4 cups is between the 13th and 15th lines from the bottom.
Step-by-step explanation:
The bottom of the cup has no line and corresponds to 0 eights.
1st line up: 1/8 cup
2nd line up: 2/8 cup this is also called 1/4 cup
3rd line up: 3/8 cup
4th line up: 4/8 cup this is also called 1/2 cup
5th line up: 5/8 cup
6th line up: 6/8 cup this is also called 3/4 cup
7th line up: 7/8 cup
8th line up: 8/8 cup this is also called 1 cup
9th line up: 9/8 cup
10th line up: 10/8 cup this is also called 1 1/4 cup
11th line up: 1 3/8 cup
12th line up: 1 4/8 cup this is also called 1 1/2 cup
13th line up: 1 5/8 cup
14th line up: 1 6/8 cup this is also called 1 3/4 cup
15th line up: 1 7/8 cup
16th line up: 1 8/8 cup this is also called 2 cups
1 3/4 cups is between the 13th and 15th lines from the bottom.
The answer is z=2m+3 so the first one is right
Answer:
142.92
Step-by-step explanation:
Density is the correct answer.
Answer:
(−0.103371 ; 0.063371) ;
No ;
( -0.0463642, 0.0063642)
Step-by-step explanation:
Shift 1:
Sample size, n1 = 30
Mean, m1 = 10.53 mm ; Standard deviation, s1 = 0.14mm
Shift 2:
Sample size, n2 = 25
Mean, m2 = 10.55 ; Standard deviation, s2 = 0.17
Mean difference ; μ1 - μ2
Zcritical at 95% confidence interval = 1.96
Using the relation :
(m1 - m2) ± Zcritical * (s1²/n1 + s2²/n2)
(10.53-10.55) ± 1.96*sqrt(0.14^2/30 + 0.17^2/25)
Lower boundary :
-0.02 - 0.0833710 = −0.103371
Upper boundary :
-0.02 + 0.0833710 = 0.063371
(−0.103371 ; 0.063371)
B.)
We cannot conclude that gasket from shift 2 are on average wider Than gasket from shift 1, since the interval contains 0.
C.)
For sample size :
n1 = 300 ; n2 = 250
(10.53-10.55) ± 1.96*sqrt(0.14^2/300 + 0.17^2/250)
Lower boundary :
-0.02 - 0.0263642 = −0.0463642
Upper boundary :
-0.02 + 0.0263642 = 0.0063642
( -0.0463642, 0.0063642)
