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levacccp [35]
3 years ago
13

Calculate the area of a circle with a diameter of 6cm

Mathematics
2 answers:
kirill115 [55]3 years ago
8 0
A≈28.27cm² is the area of the circle with diameter 6cm
as
 <span>Area of a circle = pi * r² 

Since the diameter is twice the radius, the radius is 6cm/2 which is 3cm. 

pi * 3 * 3 

= 28.2743339cm²</span>
7nadin3 [17]3 years ago
4 0
Area of circle = πd²/4,    where d = diameter
 
                      = π*6*6/4 = 9π ≈ 9 *3.1416 ≈ 28.2744 cm²

Area ≈ 28.27 cm²

Hope this explains it.

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ExtremeBDS [4]
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6 0
3 years ago
Plz help I need help
laiz [17]

Answer:

The answer is most likely -1 31/33

I have a hard time with fractions so I usually just go into my calculator and change it to a decimal. For example with -5 1/3 I would insert 1/3 into my calculator to change it to a decimal and then simply tack on the -5 to it. So in decimal form 1/3 is 0.333... so with the -5 added on its -5.333... Do the same for the other number and then divide. You will get -1.9393... all you have to do is go into your calculator and try out 11/12 or 31/33 to see which equals 0.9393... because those are the only options with a -1. In this case 31/33 equals 0.9393 s -1 31/33 is the answer

5 0
3 years ago
Someone, please explain I am so confused<br> 20 POINTS
velikii [3]

Answer:

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4 0
3 years ago
Read 2 more answers
Consider the following division of polynomials.
Bond [772]

x^4=x^2\cdot x^2. Multiplying the denominator by x^2 gives

x^2(x^2+2x+8)=x^4+2x^3+8x^2

Subtracting this from the numerator gives a remainder of

(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8

-x^3=-x\cdot x^2. Multiplying the denominator by -x gives

-x(x^2+2x+8)=-x^3-2x^2-8x

and subtracting this from the previous remainder gives a new remainder of

(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8

This last remainder is exactly the same as the denominator, so x^2+2x+8 divides through it exactly and leaves us with 1.

What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}

=x^2-x+1

and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)

=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

which matches the original numerator.

3 0
3 years ago
Read 2 more answers
Joe and grace are baking cookies.they need a total of 2 cups of sugar for the recipe. Joe has 11/10 cups of sugar and grace has3
labwork [276]
No, Joe and Grace don’t have enough together because 11/10 is only 1.1 and 3/4 is .75 and u add that together u get 1.85 which is less 2.

Grace needs 12 cups of sugar to make the cookies because 1 cups of sugar makes 6 cookies and each person is getting 3 that’s only enough for 2 people , so multiple every by 12 to get 24 people, 12 cups of sugar, and 72 cookies .
6 0
4 years ago
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