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maw [93]
2 years ago
5

Answer here plss. i suck at math

Mathematics
1 answer:
hjlf2 years ago
6 0

Answer:

Step-by-step explanation:

(3, -2 )

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The coefficient of xy in the product of (4x^2+2y) and (3x+y^2) is ...
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Here is your answer! The coefficient of xy is 6. To solve this problem, you need to multiply your two polynomials together. I used the FOIL Method- multiply the First two, the Outside two, the Inside two, and the Last two. You can see how I did it on the picture attached. Next, the answer that you get as a result from FOILing is your polynomial. If you look at the number before xy, that is the coefficient. A coefficient is a number that is right before and attached to a variable. I hope this helps you! :))

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3 years ago
A farmer sells 7.2 kg of pears and apples at the farmer's market. 2/5 of this weight is pears, and the rest is apples. how many
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Step-by-step explanation:

8 0
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Ilia_Sergeevich [38]

Answer:

416mm³

Step-by-step explanation:

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6 0
2 years ago
A deck of 52 cards contains 12 picture cards. If the 52 cards are distributed in a random manner among four players in such a wa
Mkey [24]

Answer:

The probability that each player will receive three picture cards = 0.0324

Step-by-step explanation:

As given,

A deck of 52 cards contains 12 picture cards

Remaining card = 52 - 12 = 40

So,

Total number of ways in which 12 picture card is distributed = \frac{12!}{3! 3! 3! 3!}

Now,

The Total number of ways in which Remaining cards are distributed = \frac{40!}{10! 10! 10! 10!}

So,

Total number of ways of getting 3 picture card and remaining card = \frac{12!}{3! 3! 3! 3!}× \frac{40!}{10! 10! 10! 10!}

= \frac{12! 40!}{(3!)^{4} (10!)^{4}  }

Now,

Total number of ways to distribute 52 cards so that each people get 13 card = \frac{52!}{13! 13! 13! 13!} = \frac{52!}{ (13!)^{4} }

∴ The probability = \frac{\frac{12! 40!}{(3!)^{4} (10!)^{4}  }}{\frac{52!}{(13!)^{4} }}

                            = \frac{12! 40!}{(3!)^{4} (10!)^{4}  }×\frac{(13!)^{4} }{ 52! }

                           = \frac{12! 40!}{(3!)^{4} (10!)^{4}  }×\frac{(13.12.11.10!)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41.40! }

                           = \frac{12!}{(3!)^{4}   }×\frac{(13.12.11)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}

                           = \frac{479,001,600}{(6)^{4}   }×\frac{(1716)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}

                           = 0.0324

∴ we get

The probability that each player will receive three picture cards = 0.0324

6 0
2 years ago
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