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Contact [7]
3 years ago
9

The data to the right represent the weights​ (in grams) of a random sample of 50 candies. Complete parts​ (a) through​ (f). 0.92

0.92 0.870.87 0.880.88 0.820.82 0.820.82 0.870.87 0.970.97 0.860.86 0.890.89 0.840.84 0.810.81 0.880.88 0.770.77 0.860.86 0.930.93 0.840.84 0.720.72 0.820.82 0.740.74 0.830.83 0.930.93 0.750.75 0.790.79 0.910.91 0.840.84 0.910.91 0.880.88 0.880.88 0.830.83 0.780.78 0.990.99 0.810.81 0.780.78 0.750.75 0.820.82 0.760.76 0.820.82 0.870.87 0.910.91 0.770.77 0.720.72 0.940.94 0.710.71 0.730.73 0.810.81 0.810.81 0.860.86 0.930.93 0.930.93 0.820.82 ​(a) Determine the sample standard deviation weight.
Mathematics
1 answer:
Inessa05 [86]3 years ago
5 0

Answer:

0.069

Step-by-step explanation:

The given data set is

0.92, 0.87, 0.88, 0.82, 0.82, 0.87, 0.97, 0.86, 0.89, 0.84, 0.81, 0.88, 0.77, 0.86, 0.93, 0.84, 0.72, 0.82, 0.74, 0.83, 0.93, 0.75, 0.79, 0.91, 0.84, 0.91, 0.88, 0.88, 0.83, 0.78, 0.99, 0.81, 0.78, 0.75, 0.82, 0.76, 0.82, 0.87, 0.91, 0.77, 0.72, 0.94, 0.71, 0.73, 0.81, 0.81, 0.86, 0.93, 0.93, 0.82.

Formula for mean:

Mean=\frac{\sum x}{n}

Sum of all terms = 41.98

Mean of the data set is

Mean=\frac{41.98}{50}

Mean=0.8396

Formula for standard deviation for population:

\sigma=\sqrt{\frac{\sum (x-\overline{x})^2}{n}}

Formula for standard deviation for sample:

\sigma=\sqrt{\frac{\sum (x-\overline{x})^2}{n-1}}

\sigma=\sqrt{\frac{0.231792}{50-1}}

\sigma=\sqrt{0.004730449}

\sigma=0.06877826

\sigma\approx 0.069

Therefore, the standard deviation of the data set is 0.069.

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A football field measures 300 feet in length. It can also be expressed as approximately 5 7x 10miles. If the
kogti [31]

Answer:

The question is incomplete or there are details missing.

Step-by-step explanation:

From similar parameters, if by what they mean is that the football field measures 300feet in length, which is the dimension in length, this can also be in terms of metre.

The conversion factor between ft and metre is 1ft = 0.3048m

As such, we can only have variations or the length of the field measured may have ranges of measurement,  but as it is the length of the field can not be expressed in terms of miles, the most reasonable vale of n we can get will be the least measurement in metres.

3 0
3 years ago
What is the range of the graph
sammy [17]

Answer: The range is [3, infinity).

Step-by-step explanation: The "[" means that it is apart of the graph. The ")" means it is not apart of the graph.

The graph's range (which is it's highest lowest to highest y-value), the lowest is 3 on the y axis, and then stems on to infinity. The reason why infinity is not apart of the graph is because it has no end and infinity is not a number.

4 0
1 year ago
What are the mean absolute deviation and population standard deviation of this data set? Round to the nearest tenth if necessary
tekilochka [14]

Answer:

For a data set of N elements:

{x₁, x₂, ..., xₙ}

The mean is:

M = \frac{x_1 + x_2 + ... + x_n}{N}

The mean absolute deviation is:

MAD = \frac{|x_1 - M| + ... + |x_n - M|}{N}

And the population standard deviation is:

PSD = \frac{\sqrt{|x_1 - M|^2 + ... + |x_n - M|^2} }{\sqrt{N}}

In this case, our set has 5 elements, and the set is:

{2, 4, 6, 9, 14}

The mean of this set is:

M = \frac{2 + 4 + 6 + 9 + 14}{5} = 7

The mean absolute deviation is:

MAD = \frac{|2 - 7| + |4 - 7| + |6 - 7|+ |9 - 7| + |14 - 7| }{5} = 3.6

And the population standard deviation is:

PSD =  \sqrt{\frac{|2 - 7|^2 + |4 - 7|^2 + |6 - 7|^2+ |9 - 7|^2 + |14 - 7|^2 }{5}} = 4.2

6 0
2 years ago
Help thank u so much thanks
Jlenok [28]

7.5, 7.058, 8.508,

8.58

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
U(8, 9) and V(2, 5) are the endpoints of a line segment. What is the midpoint M of that line segment?
Crazy boy [7]

Answer:

(5, 7 )

Step-by-step explanation:

Given 2 points (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

[ 0.5(x₁ + x₂ ), 0.5(y₁ + y₂ ) ]

here (x₁, y₁ ) = U(8, 9) and (x₂, y₂ ) = V(2, 5), thus

midpoint = [0.5(8 + 2), 0.5(9 + 5) ] = [0.5(10), 0.5(14) ] = (5, 7 )

6 0
3 years ago
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