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Amanda [17]
3 years ago
14

Which is the solution of the equation a + 2 = 10?

Mathematics
2 answers:
Alexandra [31]3 years ago
8 0

Hey there!

a + 2 = 10

SUBTRACT 2 to BOTH SIDES

a + 2 - 2 = 10 - 2

CANCEL out: 2 - 2 because that gives you 0

KEEP: 10 - 2 because that helps solve for the a-value

10 - 2 = a

10 - 2 = 8

Answer: Option C. a = 8

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

irina1246 [14]3 years ago
8 0
A = 8
hope this helps
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ozzi
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6 0
1 year ago
A college student is taking two courses. The probability she passes the first course is 0.73. The probability she passes the sec
zhenek [66]

Answer:

b) No, it's not independent.

c) 0.02

d) 0.59

e) 0.57

f) 0.5616

Step-by-step explanation:

To answer this problem, a Venn diagram should be useful. The diagram with the information of Event 1 and Event 2 is shown below (I already added the information for the intersection but we're going to see how to get that information in the b) part of the problem)

Let's call A the event that she passes the first course, then P(A)=.73

Let's call B the event that she passes the second course, then P(B)=.66

Then P(A∪B) is the probability that she passes the first or the second course (at least one of them) is the given probability. P(A∪B)=.98

b) Is the event she passes one course independent of the event that she passes the other course?

Two events are independent when P(A∩B) = P(A) * P(B)

So far, we don't know P(A∩B), but we do know that for all events, the next formula is true:

P(A∪B) = P(A) + P(B) - P(A∩B)

We are going to solve for P (A∩B)

.98 = .73 + .66 - P(A∩B)

P(A∩B) =.73 + .66 - .98

P(A∩B) = .41

Now we will see if the formula for independent events is true

P(A∩B) = P(A) x P(B)

.41 = .73 x .66

.41 ≠.4818

Therefore, these two events are not independent.

c) The probability she does not pass either course, is 1 - the probability that she passes either one of the courses (P(A∪B) = .98)

1 - P(A∪B) = 1 - .98 = .02

d) The probability she doesn't pass both courses is 1 - the probability that she passes both of the courses P(A∩B)

1 - P(A∩B) = 1 -.41 = .59

e) The probability she passes exactly one course would be the probability that she passes either course minus the probability that she passes both courses.

P(A∪B) - P(A∩B) = .98 - .41 = .57

f) Given that she passes the first course, the probability she passes the second would be a conditional probability P(B|A)

P(B|A) = P(A∩B) / P(A)

P(B|A) = .41 / .73 = .5616

4 0
3 years ago
The Hawks won 7 games lost 6 games and tied 2 games what percent of all the games did they win
Airida [17]
I believe the answer is 47%. 
4 0
3 years ago
Read 2 more answers
Heeelp me please ..?
Reptile [31]
Alright so first you want to find out how you take 30% off of $30.  The first step is to ask yourself, what's 30% of $30? All you have to do is make the percentage into a decimal like you did and multiply .30 times 30.  That gets you 9.  So 9 is 30% of $30, but since it said the original 30 was marked down by that much, it means subtract. 30-9=21.  
For the second part, you pretty much do the same thing but using the 21 you just got and taking away 20% this time.  Same process so .20 times 21=4.2, and take the 4.2 away from 21 to get 21-4.2=16.8.
Convert that to dollars to see that the final price is $16.80.  
Just a tip, a lot of people will forget the subtraction part after they find the percentage part.  Most of these type questions are two steps like that so don't forget to subtract when needed. Lmk if you still have questions :)
7 0
3 years ago
Given EAB and DCB are two right triangles. The figurebhas BED=BDE. point b is the midpoint of segment AC. prove EAB= DCB.
Ronch [10]

Answer:

EAB= DCB

Step-by-step explanation:

Since EAB and DCB are two right triangles then the figure ACDE is rectangular. since the total sum of rectangular 360° there is no options except to be rectangular. If the figure ACDE is rectangular then the two sides AE & CD are equal. Since Point b is midway point the two sides are also equal.

3 0
3 years ago
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