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vampirchik [111]
3 years ago
10

Find each sum or difference

Mathematics
1 answer:
KIM [24]3 years ago
6 0
(1.)
\frac{5}{10} - \frac{3}{10} \\ = \frac{2}{10} \\ = \frac{1}{5}
(2.)
\frac{1}{2} + \frac{3}{4} \\ = \frac{1 \times 2}{2 \times 2} + \frac{3}{4} \\ = \frac{2}{4} + \frac{3}{4} \\ = \frac{5}{4}
(3.)
\frac{1}{6} + \frac{3}{8} \\ = \frac{1 \times 4}{6 \times 4} + \frac{3 \times 3}{8 \times 3} \\ = \frac{4}{24} + \frac{9}{24} \\ = \frac{13}{24}
(4.)
\frac{7}{8} - \frac{5}{12} \\ = \frac{7 \times 3}{8 \times 3} - \frac{5 \times 2}{12 \times 2} \\ = \frac{21}{24} - \frac{10}{24} \\ = \frac{11}{24}
(5.)
\frac{7}{8} - \frac{3}{4} \\ = \frac{7}{8} - \frac{3 \times 2}{4 \times 2} \\ = \frac{7}{8} - \frac{6}{8} \\ = \frac{1}{8}
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