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Rudiy27
3 years ago
9

$15,000 at 15% compounded annually for 5 years

Mathematics
1 answer:
svlad2 [7]3 years ago
8 0

Answer:

p=$15000

R=15%

t=5years

compound amount CI=?

Step-by-step explanation:

we have

  • CI=p(1+R/100)^t=$15000(1+15/100)^5=$15000×1/15^5=$30170.35
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4s=p

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4s/4=p/4

s=1/4p

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Which of the following numbers is different
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(D) 1/4%

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Caroline bought 20 shares of stock at 10 1/2, and after 10 months the value of the stocks was 11 1/4. If Caroline were to sell a
joja [24]
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Find the value of the variable What is x?
yaroslaw [1]

Answer:

x = 7

Step-by-step explanation:

I think there may be other ways to do this ... but this is one I  guess....

one angle= 90 ( given)

the other = 45 (given)

the third = 90 + 45 + a = 180  

(all angles of triangles is 180 [angle sum property])

                a = 180 - 135

                   = 45

The base angles are equal so that means it is a isoscles triangle. In isoscles triangle, two sides are equal ,  so

if one side is 7

the x is 7 too

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I think this is right

5 0
2 years ago
13. The least common multiple of two non-zero integers a and b is the unique positive integer m such that (i) m is a common mult
Vlad [161]

Answer:

[a,b] divides n

Step-by-step explanation:

Let us denote the least common multiple of a and b [a,b]=m.

We want to prove that m divides n, where n is a multiple of a and b.

We suppose m does not divide n, then by the Division Theorem, there exists q and r integers such that:

(1) ... n=mq+r, where 0<r<m

As n is a multiple of a and b, there exists s and t integers such that:

sa=n and tb=n

Same thing happens to m as it is the least common multiple, there exists u and v such that:

ua=m and vb=m

So (1) has the following form:

n=mq+r ⇒ sa=uaq+r ⇒sa-uaq=r⇒(s-uq)a=r and

n=mq+r ⇒ tb=vbq+r ⇒ tb-vbq=r⇒ (t-vq)b=r

So r is a multiple of a and b, but r<m which is a contradiction as, m is the least common multiple of a and b. So this concludes the proof.

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As m= vb, then \frac{m}{b} is an integer, lets say \frac{m}{b}=v; and as m=ua, then \frac{m}{a}=u.

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4 0
3 years ago
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