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Pani-rosa [81]
3 years ago
5

Which equations are correct?

Mathematics
1 answer:
stepan [7]3 years ago
5 0

Answer:

3y^5(2y^3+3)=−6y^8−9y^5

−2c^6(5c^3+6)=−10c^9−12c^6

are the correct equations.

Step-by-step explanation:

If you simply all these equations you will get following equations :

when bases are same and are in multiplication we add the exponents.

−4b^4(5b^2+6)=−20b^6−24b^4

−5x^3(3x^3+2)=−15x^6−10x^3

−3y^5(2y^3+3)=−6y^8−9y^5

−2c^6(5c^3+6)=−10c^9−12c^6

so equation 3 and 4 are correct.

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How do the particular characteristics of an ecosystem arise?
kumpel [21]

Answer:

Step-by-step explanation:

Ecosystems form in response to the unique but predictable climate of each geographic area. And since elevation and topography affect climate, ecosystems are different at different elevations. The life in any given ecosystem is the direct result of elevation, topography, and temperature, and rainfall patterns.

4 0
3 years ago
76°<br> x<br> 135°<br> 810<br> X =<br> X=<br> y=
enot [183]

Answer:

x = 68º

Step-by-step explanation:

This trapezoid is a quadrilateral.  All degrees in a quadrilateral have to add up to 360º.  

76º + 135º + 81º + xº = 360º

292º + xº = 360º

xº = 360º - 292º

xº = 68º

5 0
3 years ago
The length of the box is 2x - 2 and the width is x - 5. Find the perimeter. (HINT: p= 2L + 2W) Choose one.
trasher [3.6K]

Answer:

Option D: 6x-14 is the correct answer.

Step-by-step explanation:

Given that:

Length of the box = L = 2x-2

Width of the box = W = x-5

Perimeter is defined by the sum of length of all sides of the box.

Perimeter of the box = P = 2L + 2W

Perimeter of box = 2(2x-2) + 2(x-5)

Perimeter = 4x-4+2x-10

Perimeter = 6x-14

The perimeter of the box is 6x-14.

Hence,

Option D: 6x-14 is the correct answer.

6 0
3 years ago
Aubrey has a new art box in the shape of a rectangular prism. The box is 12 cm by 5cm
tia_tia [17]
LWH-LWH
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=1200-32
=1168 cubic cms
5 0
3 years ago
Read 2 more answers
Lim 1 + cos TX<br>5.<br>x&gt;1 tanưrex​
Brums [2.3K]

Answer: 1/2

\lim_{x \to 1}\frac{1+cos \pi x}{tan^{2}\pi x }\\\\ = \lim_{x \to 1} \frac{1+cos\pi x}{\frac{sin^{2}\pi x }{cos^{2}\pi x } } \\\\\\= \lim_{x \to 1}\frac{cos^{2}\pi x(1+cos\pi x) }{sin^{2}\pi x } \\\\\\= \lim_{x \to 1} \frac{cos^{2}\pi x(1+cos\pi x)}{1-cos^{2}\pi x }  \\\\= \lim_{x \to 1} \frac{cos^{2}\pi x }{1-cos\pi x} \\\\= \lim_{x \to 1}\frac{cos^{2}\pi .1 }{1-cos\pi .1}\\\\= \lim_{x \to 1}\frac{1}{1-(-1)}\\\\=\frac{1}{2}

Step-by-step explanation:

5 0
3 years ago
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