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Pani-rosa [81]
3 years ago
5

Which equations are correct?

Mathematics
1 answer:
stepan [7]3 years ago
5 0

Answer:

3y^5(2y^3+3)=−6y^8−9y^5

−2c^6(5c^3+6)=−10c^9−12c^6

are the correct equations.

Step-by-step explanation:

If you simply all these equations you will get following equations :

when bases are same and are in multiplication we add the exponents.

−4b^4(5b^2+6)=−20b^6−24b^4

−5x^3(3x^3+2)=−15x^6−10x^3

−3y^5(2y^3+3)=−6y^8−9y^5

−2c^6(5c^3+6)=−10c^9−12c^6

so equation 3 and 4 are correct.

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iogann1982 [59]
Ok in 2001 the Barnes had 45,000, and 12% was dedicated to savings.

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so 10% of 45000 is (10/100) * 45000 or just 4500, you simply chop off a zero

so, it went from 45000 to 45000 + 4500 or 49500

now, they do their budget the same, savings is 12% in 2002, just like in 2001, alrite, how much is 12% of 49500? well, 12% of anything is just (12/100) * anything

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3 years ago
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Answer:

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Step-by-step explanation:

6 0
4 years ago
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Find the value of B - A if the graph of Ax + By = 3 passes through the point (-7,2), and is parallel to the graph of x + 3y = -5
sukhopar [10]

Answer:

The found values are:

A = 1/3

B = -8/3

Step-by-step explanation:

We know that general equation is given by:

y = mx + c

where m is the slope and c is a constant.

x + 3y = -5

y = -(1/3)x - 1/3(5)

Slop of the equation is -(1/3). As parallel line have same slope substitute it in the first equation:

Ax + By = 3

By = -Ax - 3

By = (1/3)x - 3

Hence, A = 1/3

Substitute point (-7,2) into the equation:

B(2) = (1/3)(-7) -3

B(2) = -7/3 - 3

B(2) = -16/3

B = -16/6

B = -8/3

4 0
3 years ago
Help pls. I need answers quick.​
mr Goodwill [35]
-1/2
negative half
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8 0
3 years ago
Hey, please I need help with this
gavmur [86]

Answer:

∠CGD is 52°

Step-by-step explanation:

∠AGB is 90° and its corresponding ∠EGD is also 90°

90+38= 128

180-128= 25

5 0
3 years ago
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