Define your variables:
Q: number of quarters
D: number of dimes
Next, create your equations
Q = 2D-4
25Q+10D=200
Because one variable (Q) is already written in terms of the other variable, D, you can already start solving with substitution.
25(2D-4)+10D=200
50D-100+10D=200
60D=300
D=5
Substitute D back into the other equation to find Q.
Q=2D-4
Q=2(5)-4
Q=6
Substitute D and Q into the second equation to check.
25Q+10D=200
25(6)+10(5)=200
150+50=200
This works, so the answer is right! Bill has 6 quarters and 5 dimes.
I think it would just be n rad n
The following are true:-
First choice
Third choice.
The last choice
(1,2) is a solution to the system of equations
