Cassidy is going to the county fair with her friends but can only stay at the fair for 4 hours. The fair offers two different pr
2 answers:
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SA= Lateral Area + Area (of base)
Lateral area = perimeter of base x height
An isosceles triangle has two congruent base segments. The hypotenuse of an isosceles right triangle is (length of base segment) x (the square root of 2). I did the math for you (shown above) to get 5 as a base.
So 5 + 5 + square root of 50 is your perimeter
Multiply the perimeter times your height (8) and you get the lateral area.
Add your lateral area to the base area (triangle = 1/2 bh)
LA = 136.568...
Area of Triangle base = 12.5
Surface area = 149.068... square cm
Lateral area = perimeter of base x height
An isosceles triangle has two congruent base segments. The hypotenuse of an isosceles right triangle is (length of base segment) x (the square root of 2). I did the math for you (shown above) to get 5 as a base.
So 5 + 5 + square root of 50 is your perimeter
Multiply the perimeter times your height (8) and you get the lateral area.
Add your lateral area to the base area (triangle = 1/2 bh)
LA = 136.568...
Area of Triangle base = 12.5
Surface area = 149.068... square cm
Answer with Step-by-step explanation:
We are given that two independent tosses of a fair coin.
Sample space={HH,HT,TH,TT}
We have to find that A, B and C are pairwise independent.
According to question
A={HH,HT}
B={HH,TH}
C={TT,HH}
{HH}
={HH}
={HH}
P(E)=
Using the formula
Then, we get
Total number of cases=4
Number of favorable cases to event A=2
Number of favorable cases to event B=2
Number of favorable cases to event C=2
If the two events A and B are independent then
Therefore, A and B are independent
Therefore, B and C are independent
Therefore, A and C are independent.
Hence, A, B and C are pairwise independent.