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Romashka [77]
3 years ago
10

Need help with this today

Mathematics
1 answer:
madam [21]3 years ago
5 0

Answer:

a) 2.5

b) x = 10

Step-by-step explanation:

a) \:  \frac{10}{4}  =  \frac{5}{2}  = 2.5

b) \frac{10}{4}  =  \frac{25}{x}   \\  \\ 10x = 25 \times 4 \\ 10x = 100 \\  \\ x =  \frac{100}{10}  = 10 \\  \\ x = 10

I hope I helped you^_^

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Suppose a city with population of 400,000 has been growing at a rate of ​5% per year. If this rate​ continues, find the populati
kakasveta [241]

The number of years value isn't given, we could use an hypothetical value, which can be substituted for the correct number of years given in your exercise in other to find the exact answer.

Using a t value of 10 years

Answer:

651558

Step-by-step explanation:

Given that:

Initial population, P0= 400,000

Growth rate, r = 5%

Using the relation :

P(t) = P0 * (1 + r)^t

t = number of years = 10

P(10) = 400000 * (1 + 0.05)^10

P(10) = 400000 * (1.05)^10

P(10) = 400000 * 1.628894626777

P(10) = 651557.8507

= 651558 nearest whole number.

Recall that, the t value used is hypothetical and should be replaces with te exact value given in your question.

7 0
3 years ago
!!!!HELP ME PLZZZZZZZZZZZZZ
Zolol [24]

Answer:

2) Yes

3) No

4) Yes

5) 2x + 8

6) 5(x - 8)

7) 3x + 21

Hope this helps :)

5 0
3 years ago
Is 0.062 equal to .062
Alona [7]
 yes. The zero to the left of the decimal point does not affect the overall value of the problem when removed, since it is zero.
4 0
3 years ago
Read 2 more answers
What is (f⋅g)(x)?<br><br><br><br> f (x) =x^4−9<br><br> g (x) =x^3+9
mojhsa [17]
<span>(f⋅g)(x)=f(x)*g(x) 
</span>f(x)*g(x) = (x⁴−9)(x³+9)=x⁴x³+9x⁴-9x³-81=x⁷+9x⁴-9x³-81
(f⋅g)(x)=x⁷+9x⁴-9x³-81
3 0
4 years ago
What is the answer plz help plz I need so much help
snow_lady [41]

The inequality is 700<500+0.05s.
Solve it like an equation by isolating the variable (the variable is s).
700<500+0.05s
-500 -500
200<0.05s
÷0.05 ÷0.05
4000<s
s>4000

Jasmine needs more than $4000 in sales. s>4000
The inequality is 700<500+0.05s.



3 0
3 years ago
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