Biologists study biotic factors, and all other living things.
I would say carbon monoxide
Firstly because the image shows two different atoms bonded so it cannot be nitrogen or krypton
Secondly sulphur dioxide has 3 atoms bonded (two oxygens and a sulphur atom) so it can’t be that
Finally it can’t be hydrogen chloride because chloride is significantly larger than hydrogen
Thus it must be carbon monoxide as carbon and oxygen are bonded (CO) and are both relatively similar in size
Answer: true
Explanation: according to the law of conservation of mass the mass of reactants would equal the mass of the products
Yes the statement is True i.e. when a metal reacts with a nonmetal, the metal tends to gain electrons.
A metal tends to gain or lose electrons depending on whether a nonmetal tends to gain electrons or a metal tends to lose electrons, if both a nonmetal and a nonmetal tend to lose electrons and if neither of the other choices apply. Or metal frequently pulls electrons. It turns out that lines are formed when a metal combines with a non-metal because electrons are transferred from the metal atoms to the non-metal atoms, demonstrating that the metal is giving electrons. It loses electrons and transfers them to non-metals, or we could say that it does both. Nonmetal further acquires electrons. As a result, when a metal reacts normally, that is the acceptable answer. Metals typically lose electrons when creating an ionic compound, while nonmetals typically gain electrons. Since the valence shell is the outermost shell that matters, the reason is that they have fewer electrons in their valence shells, which makes it simple for them to lose electrons rather than gain them.
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Answer:
216.0cm³ of ore must be processed
Explanation:
First, we need to know how many grams of gold we need to obtain $100.00
<em>Mass of gold to obtain $100.00:</em>
$100.00 gold * (1 troy oz / $818) = 0.122 troy oz
0.122 troy oz * (1.0lb / 14.6troy oz) = 8.37x10⁻³ lb
8.37x10⁻³ lb * (454g / 1lb) =
3.80g of gold we need to obtain $100.00
Now, the ore contain 0.22g of gold in 100g and the density of the ore is 8.0g/cm³. We can solve the cubic centimeters to obtain $100.00:
<em>Cubic centimeters of ore:</em>
3.80g Gold * (100g Ore / 0.22g Gold) = 1727.9g of Ore
1727.9g Ore * (1cm³ / 8.0g Ore) =
<h3>216.0cm³ of ore must be processed</h3>