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marusya05 [52]
3 years ago
10

Which formula can represent hydrogen ions in an aqueous solution?

Chemistry
1 answer:
faltersainse [42]3 years ago
6 0

Answer:

H30+(aq)

Explanation:

im almost postive this is correct ,but if not its OH-(aq)

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what pressure will be needed to reduce the volume of 77.4 l of helium at 98.0 kpa to a volume of 60.0 l? 76 kpa 126 kpa
nekit [7.7K]
The system follow the Boyle's Law:

P_1\cdot V_1 = P_2\cdot V_2\ \to\ P_2 = \frac{P_1\cdot V_1}{V_2} = \frac{98\ kPa\cdot 77.4\ L}{60.0\ L} = \bf 126.4\ kPa
6 0
3 years ago
For the reaction below, determine the standard free energy change, δg o. cu(s) + sn2+(aq) → cu2+(aq) + sn(s) e o cell =–0.48 v v
Salsk061 [2.6K]

Answer:

92.6 kJ.

Explanation:

<em>∵ ΔG°rxn = - nFE°cell,</em>

Where, ΔG°rxn is the standard free energy change (J).

n is the no. of electrons in the reaction (n =2).

F is Faraday constant (C/mol) (F = 96500 C/mol).

E°cell is the standard cell potential (E°cell = - 0.48 V).

<em>∴ ΔG°rxn = - nFE°cell </em>= - (2)(96500 C/mol)(- 0.48 V) = <em>92640 J = 92.64 kJ.</em>

7 0
3 years ago
What type(s) of intermolecular forces are expected between ch3conhch3 molecules?
hoa [83]
Hydrogen bonds.
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3 0
3 years ago
What happens to the particles when heat is removed
BaLLatris [955]
I think the particle starts to move slowly around because no heat or pressure is applied to it
6 0
4 years ago
Read 2 more answers
What fraction of a Sr-90 sample remains unchanged after 87.3 years
jolli1 [7]
The answer is 1/8.

Half-life is the time required for the amount of a sample to half its value.
To calculate this, we will use the following formulas:
1. (1/2)^{n} = x,
where:
<span>n - a number of half-lives
</span>x - a remained fraction of a sample

2. t_{1/2} = \frac{t}{n}
where:
<span>t_{1/2} - half-life
</span>t - <span>total time elapsed
</span><span>n - a number of half-lives
</span>
The half-life of Sr-90 is 28.8 years.
So, we know:
t = 87.3 years
<span>t_{1/2} = 28.8 years

We need:
n = ?
x = ?
</span>
We could first use the second equation, to calculate n:
<span>If:
t_{1/2} = \frac{t}{n},
</span>Then: 
n = \frac{t}{ t_{1/2} }
⇒ n = \frac{87.3 years}{28.8 years}
⇒ n=3.03
<span>⇒ n ≈ 3
</span>
Now we can use the first equation to calculate the remained amount of the sample.
<span>(1/2)^{n} = x
</span>⇒ x=(1/2)^3
⇒x= \frac{1}{8}<span>
</span>
8 0
4 years ago
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