Answer:
92.6 kJ.
Explanation:
<em>∵ ΔG°rxn = - nFE°cell,</em>
Where, ΔG°rxn is the standard free energy change (J).
n is the no. of electrons in the reaction (n =2).
F is Faraday constant (C/mol) (F = 96500 C/mol).
E°cell is the standard cell potential (E°cell = - 0.48 V).
<em>∴ ΔG°rxn = - nFE°cell </em>= - (2)(96500 C/mol)(- 0.48 V) = <em>92640 J = 92.64 kJ.</em>
Hydrogen bonds.
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I think the particle starts to move slowly around because no heat or pressure is applied to it
The answer is 1/8.
Half-life is the time required for the amount of a sample to half its value.
To calculate this, we will use the following formulas:
1.

,
where:
<span>n - a number of half-lives
</span>x - a remained fraction of a sample
2.

where:
<span>

- half-life
</span>t - <span>total time elapsed
</span><span>n - a number of half-lives
</span>
The half-life of Sr-90 is 28.8 years.
So, we know:
t = 87.3 years
<span>

= 28.8 years
We need:
n = ?
x = ?
</span>
We could first use the second equation, to calculate n:
<span>If:

,
</span>Then:

⇒

⇒

<span>⇒ n ≈ 3
</span>
Now we can use the first equation to calculate the remained amount of the sample.
<span>

</span>⇒

⇒

<span>
</span>