There are two dozen apples for three pies so there would be 2/3 of a dozen apples for 1 pie. 2/3 times 4 is 8/3 which simplifies to 2 2/3.
I this helps you out with your problems
Have a nice day
Because

is increasing, you know that

, which means

must be concave upward over its domain, so A is strue.
By the same fact above, you also know that D must be true.
Relative extrema occur for points where

, and you know that the graph of

crosses the x-axis at

, so this is also true.
That leaves B. Why is it false? Inflection points occur at points where

, where the sign of

changes to either side of

. But you know that

is always true, so there is no such

that makes

.
vertex (1,-1) axis of symmetry is x=1, domain all real numbers (i think neg ys) range y is less equal than -1, y increases as x less 0 bug IMO x decreases