Try this explanation:
1. if to re-write the given function as:
then it is possible to define its range:
2)
![\lim_{x \to+ \infty}[1- \frac{C}{e^x+C}]=1; \\ \lim_{x \to- \infty}[1- \frac{C}{e^x+C}]=0](https://tex.z-dn.net/?f=%20%5Clim_%7Bx%20%5Cto%2B%20%5Cinfty%7D%5B1-%20%5Cfrac%7BC%7D%7Be%5Ex%2BC%7D%5D%3D1%3B%20%20%5C%5C%20%5Clim_%7Bx%20%5Cto-%20%5Cinfty%7D%5B1-%20%5Cfrac%7BC%7D%7Be%5Ex%2BC%7D%5D%3D0)
answer: (0;1)
1. if to re-write the given function as:
then it is possible to define its range:
2)
answer: (0;1)
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1 answer:
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Answer:
see below
Step-by-step explanation:
The odd degree (7) tells you the end behaviors are in opposite directions. The negative leading coefficient (-4) tells you the sign of y will be opposite the sign of x.
For x going toward negative infinity, y goes toward positive infinity.
For x going toward positive infinity, y goes toward negative infinity.
