1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
iogann1982 [59]
3 years ago
8

A company charges 0.10 for each letter engraved bobby plans to spend no more than 5.00 on the engraving on a jewelry box right a

nd solve any quality to find the maximum number of letters he can have engraved
Mathematics
1 answer:
zlopas [31]3 years ago
8 0

Answer:

the maximum number of letters he can engrave is 50.

Step-by-step explanation:

A company charges $0.10 for each letter engraved bobby plans to spend no more than $5.00 on the engraving.

The maximum number of letters he can engrave can be done by division

5/0.10

= 50 letters.

You might be interested in
john currently has enough money to buy 45 books. If the cost of each book was 10 cents less.john could buy 5 more books. How muc
SVEN [57.7K]
Let the cost of one book= x cents
Let the money john have= y cents

According to the question,

45x=y                                               ...eq(1)
(45+5)(x-5)=y                                  
50(x-5)=y                                         
50x-250=y                                        ...eq(2)

On subtracting (1) from (2).
(50x-250)-45x=y-y
5x-250=0
x=250/5
x=50

Thus, cost of each book is 50 cents and john has 2250 cents.

Hope it helps.
Don't feel shy in saying thx if it helps.


4 0
3 years ago
There are 8 sophomores on the academic team. At the last competition, they each took the math test. Their scores were 82%, 92%,
castortr0y [4]

Median would be 80.75 or 79


8 0
3 years ago
Read 2 more answers
Please help i cannot get it ​
Lerok [7]
Pi symbol raised to the 3 times x raised to the 4
7 0
2 years ago
Please help, its urgent. (Question Below)
rusak2 [61]

The highest common factor of the numbers 210 and 308 is 4.

<h3>What is the highest common factor?</h3>

The highest factor of the two numbers which divides both the numbers is called as greatest common factor or HCF.

The highest common factor will be calculated by finding the factors of the two numbers. The factors of the two numbers are as follows:-

308   =  2 x  2   x  7  x  11

210   =  2  x  2   x  3  x  17

We can see that the 2  x  2  =  4 is the highest factor which is common between the two numbers 210 and 308. So 4 is the HCF which can divide both the numbers 210 and 308.

Therefore the highest common factor of the numbers 210 and 308 is 4.

To know more about HCF follow

brainly.com/question/219464

#SPJ1

4 0
2 years ago
What is the exact value of tan(-π/3)?<br>A. -√3<br>B. -√3/3<br>C.√3/3<br>D. √3​
Dimas [21]

\tan \left(-\dfrac{\pi}3\right)\\\\=-\tan \left(\dfrac{\pi}3\right)\\\\=-\sqrt 3

5 0
2 years ago
Other questions:
  • In ΔKLM, the measure of ∠M=90°, the measure of ∠L=55°, and LM = 59 feet. Find the length of KL to the nearest tenth of a foot.
    8·2 answers
  • a recipe for a loaf of bread calls for 2/3 of a cup of flour if Milo used 12 cups of flour how many loafs of bread did he prepar
    9·1 answer
  • The masses of two objects are compared during a physics experiment. It is determined that object A has a mass of 4×10−3 grams an
    6·1 answer
  • Error Analysis A problem on a test says that 70% of people enjoy the beach. The students are
    9·1 answer
  • If 3 meters of fence cost 29$, how much would it cost lateisha to build the entire fence around her yard? write a proportion to
    13·1 answer
  • What's the square root of 30 round to nearest hundredth
    10·2 answers
  • The perimeter of a rectangle is 188 meters. The width is 2 meters shorter than triple the length. Find the area of the rectangle
    13·1 answer
  • Write 375 cm3 in millilitres.
    6·1 answer
  • Solve the equation <br>4(2^m+1)-16^m=0​
    5·2 answers
  • Find the slope below 4,1 4,-4
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!