Answer:
y=-
x+
Step-by-step explanation:
First, calculate the slope of the line that is perpendicular to the equation of line we are asked to find
m=(y2-y1)/(x2-x1)
=(2-(-4))/(-2-1)
=6/-3
=-2
in this equation the slope is 2, and to find the first equation, use y=mx+b
use the point (1, -4) to find b
-4=(2)(1)+b
-4=2+b
b=-6
the first equation of the line is y=2x-6
to find the x intercept of that line substitute 0 for y
0=2x-6
2x=6
x=3
the slope of a line perpendicular to this would be the opposite reciprocal of the slope which would be equal to -1/2
for the second equation of the line to pass thorugh the x-intercept of the first line, it must pass through (3, 0), so substitute and solve for b
y=mx+b
0=(-1/2)(3)+b
b=3/2
thus the equation of the line that is perpendicular to the line through (1,-4) and (-2, 2) and passes through the x intercept of that line is y=-
x+3/2
Hey! Glad I can help!!!
0.4 is the tenth in there.
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I'm probably wrong but I think A.
r - 4/5r = 1/5r + 1
Subtract 1/5r from each side: r - 4/5r - 1/5r = 1
Combine all the 'r' terms on the left side:
r - 5/5r = 1
r - r = 1
0 = 1
There is no value of 'r' that can make ' 0 = 1 ' a true statement.
So the equation has <em>no solution</em>.
Answer:
-18
Step-by-step explanation:
Given:
f(x)=4-x^2 and g(x) =6x
h(3) = (g-f)(3)
= 6x - (4x^2)
= 6*3 -(4*3^2)
= 18 - 4*9
= -18