Given :
Two equation 
and 
.
To Find :
The point of intersection of these lines .
Solution :
We will use elimination method :
From equation 1 :
Putting value of 
in equation 2 we get :
Putting value of 
in equation 1 we get :
Therefore , point of interaction is 
.
Hence , this is the required solution .
1st: toute valeur de x rend I'<span>équation vraie
tous les nombres r</span><span>éels
2nd: r</span><span>ésoudre l'équation pour x en trouvant a, b et c du quadratique puis en appliquant la formule quadratique
x = 2 ± i</span>
Answer:
v=3.6
Step-by-step explanation:
Answer: x=10 and y=25
Step-by-step explanation:
ok, so since we know straight angles=180 degrees, so since one part=100, the other smaller angle=80. This means that 11x-30=80 and 5y-25=100. 11*10=110, and 110-30=80, so x=10. 5*25=125, and 125-25=100, so y=25. And lol. me too. When I used to do these problems, I was stuck for a very, very long time. Just try to use logic most of the time.
Please enclose that -3/5 in parentheses: <span>y+1= (−3/5)(x−4)
</span>
Let's use the intercept method to graph this line.
First, set x = 0 and find y; this y will be the y-coordinate of the vertical intercept:
y+1= (−3/5)(0−4) => y = -1 + 12/5 = -5/5 + 12/5 = 7/5. Plot (0, 7/5).
Next, set y = 0 and find x; this will give us the coordinate of the horiz. int.:
0+1= (−3/5)(x−4) => -5/3 = x - 4, or x = 4- 5/3, or x = 7/3. Plot (7/3, 0).
Now draw a straight line thru these two points.
