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Sergeeva-Olga [200]
2 years ago
9

Its algebra just forgot how to do the work please do the work 50 points

Mathematics
1 answer:
Ira Lisetskai [31]2 years ago
5 0

Answer:

Step-by-step explanation:

f(2) = 6        (what multiplies 2 to equal 6?)*2 = 6

It seems like x gets multiplied by three. Let's check the next one:

f(-1) = -3

Ah ha! We were right. Let's check one more time:

2 * 3 = 6

-1 * 3 = -3

f(x) just means what is f when x is any number. This function that we covered above is: f(x) = 3x

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P = 128, making all values equal up to 180
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The square root of 104 is between which two integers?
olganol [36]

Answer: 10 and 11

Step-by-step explanation: The best way to think about it is to think of the squares of numbers that equal close to 104. 10 squared is 100, and 11 squared is 121. Since 104 is between these two, we can assume that the square root of 104 must be in between their square roots, 10 and 11.

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Convert the angle - 3 radians to degrees, rounding to the nearest 10th
dlinn [17]

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171.9 degrees.

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3 years ago
The mean of three number is 15. if 2 of the numbers are 18 and 16 what is the third number​
MrMuchimi

Answer:

11

Step-by-step explanation:

The mean is calculated as

mean = \frac{sum}{count}

let the third number be x , then

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3 0
3 years ago
HELP ME PLEASE
solmaris [256]

Answer:

The initial mass of the sample was 16 mg.

The mass after 5 weeks will be about 0.0372 mg.

Step-by-step explanation:

We can write an exponential function to model the situation.

Let the initial amount be A. The standard exponential function is given by:

P(t)=A(r)^t

Where r is the rate of growth/decay.

Since the half-life of Palladium-100 is four days, r = 1/2. We will also substitute t/4 for t to to represent one cycle every four days. Therefore:

\displaystyle P(t)=A\Big(\frac{1}{2}\Big)^{t/4}

After 12 days, a sample of Palladium-100 has been reduced to a mass of two milligrams.

Therefore, when x = 12, P(x) = 2. By substitution:

\displaystyle 2=A\Big(\frac{1}{2}\Big)^{12/4}

Solve for A. Simplify:

\displaystyle 2=A\Big(\frac{1}{2}\Big)^3

Simplify:

\displaystyle 2=A\Big(\frac{1}{8}\Big)

Thus, the initial mass of the sample was:

A=16\text{ mg}

5 weeks is equivalent to 35 days. Therefore, we can find P(35):

\displaystyle P(35)=16\Big(\frac{1}{2}\Big)^{35/4}\approx0.0372\text{ mg}

About 0.0372 mg will be left of the original 16 mg sample after 5 weeks.

5 0
3 years ago
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