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2 years ago

Its algebra just forgot how to do the work please do the work 50 points

Mathematics

1 answer:

Ira Lisetskai [31]2 years ago

5 0

Answer:

Step-by-step explanation:

f(2) = 6 (what multiplies 2 to equal 6?)*2 = 6

It seems like x gets multiplied by three. Let's check the next one:

f(-1) = -3

Ah ha! We were right. Let's check one more time:

2 * 3 = 6

-1 * 3 = -3

f(x) just means what is f when x is any number. This function that we covered above is: f(x) = 3x

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Find the area of the shaded region

kodGreya [7K]

Answer: 21.994 cm²

Step-by-step explanation:

Area of the shaded region = Area of the bigger circle - the areas of the two smaller circles.

Formula for finding area of a circle = πr² where π is a constants . It has value of 22/7 or 3.142

Now area of the bigger circle = 3.142 x 3²

= 3.142 x 9

= 28.278 cm² Now are of the two smaller triangle = 3.142 x 1² x 2

= 6.284 cm².

Therefore are of the shaded region = 28.278 - 6.284

= 21.994 cm²

7 0

3 years ago

alpha needs to make jerseys for its 33 teachers and set aside some money for their budget to pay for them. the staff has decided

marishachu [46]

So it would be $38 multiplied by 33 which is: $1,254

4 0

3 years ago

Select the decimal that is equivalent to 45/54

lina2011 [118]

Answer:

.83

Step-by-step explanation:

if brainiest is earned its greatly Appreciated

6 0

3 years ago

A random sample of n = 45 observations from a quantitative population produced a mean x = 2.5 and a standard deviation s = 0.26.

oee [108]

Answer:

P-value (t=2.58) = 0.0066.

Note: as we are using the sample standard deviation, a t-statistic is appropiate instead os a z-statistic.

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the population mean μ exceeds 2.4.

Then, the null and alternative hypothesis are:

$H_0: \mu=2.4\\\\H_a:\mu> 2.4$

The significance level is 0.05.

The sample has a size n=45.

The sample mean is M=2.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.26.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.26}{\sqrt{45}}=0.0388$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{2.5-2.4}{0.0388}=\dfrac{0.1}{0.0388}=2.58$

The degrees of freedom for this sample size are:

$df=n-1=45-1=44$

This test is a right-tailed test, with 44 degrees of freedom and t=2.58, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t>2.5801)=0.0066$

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

7 0

3 years ago

A store is having a sale on jelly beans and trail mix. For 3 pounds of jelly beans and 2 pounds of trail mix, the total cost is

Nata [24]

the cost for each of jelly beans and each pound of trail mix is $2.5 and $1.75

<u>Step-by-step explanation:</u>

Given A store is having a sale on jelly beans and trail mix. For 3 pounds of jelly beans and 2 pounds of trail mix, the total cost is $11. For 5 pounds of jelly beans and 6 pounds of trail mix, the total cost is $23 . We have to find the cost for each pound of trail mix and each pound of jelly beans.

Let the cost of each pound of trail mix is $y.

and the cost of each pound of jelly beans is $x.

According to question,

For 3 pounds of jelly beans and 2 pounds of trail mix, the total cost is $11.

⇒ $3x+2y=11$ → (1)