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3 years ago

8.75x10^-3 in standard form

Mathematics

1 answer:

Alexeev081 [22]3 years ago

8 0

8.75x0.001=0.00875
that is the number written in standard form

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I NEED HELPPPPPPP

dexar [7]

Step-by-step explanation:

<h3 /><h3 /><h3><u>Given : 1/16 ÷ 1/81 + - 1/8To find: multiplicative inverseSolution:a multiplicative inverse is basically a reciprocalMultiplicative inverse of number is the number which if multiplied by original number result in 11/16 ÷ 1/81 + -1/81/16 ÷ 1/81 = 81/16+ - 1/8 = - 1/881/16 - 1/8= 81/16 - 2/16= (81 - 2)/16= 79/16Multiplicative inverse = 16/79</u></h3>

4 0

3 years ago

Because of their connection with secant lines, tangents, and instantaneous rates, limits of the form ModifyingBelow lim With h

Gre4nikov [31]

Answer:

$\dfrac{1}{2\sqrt{x}}$

Step-by-step explanation:

$f(x) = \sqrt{x} = x^{\frac{1}{2}}$

$f(x+h) = \sqrt{x+h} = (x+h)^{\frac{1}{2}}$

We use binomial expansion for $(x+h)^{\frac{1}{2}}$

This can be rewritten as

$[x(1+\dfrac{h}{x})]^{\frac{1}{2}}$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}$

From the expansion

$(1+x)^n=1+nx+\dfrac{n(n-1)}{2!}+\ldots$

Setting $x=\dfrac{h}{x}$ and $n=\frac{1}{2}$ ,

$(1+\dfrac{h}{x})^{\frac{1}{2}}=1+(\dfrac{h}{x})(\dfrac{1}{2})+\dfrac{\frac{1}{2}(1-\frac{1}{2})}{2!}(\dfrac{h}{x})^2+\tldots$

$=1+\dfrac{h}{2x}-\dfrac{h^2}{8x^2}+\ldots$

Multiplying by $x^{\frac{1}{2}}$ ,

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}=x^{\frac{1}{2}}+\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}=\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$\dfrac{x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}}{h}=\dfrac{1}{2x^{\frac{1}{2}}}-\dfrac{h}{8x^{\frac{3}{2}}}+\ldots$

The limit of this as $h\to 0$ is

$\lim_{h\to0} \dfrac{f(x+h)-f(x)}{h}=\dfrac{1}{2x^{\frac{1}{2}}}=\dfrac{1}{2\sqrt{x}}$ (since all the other terms involve $h$ and vanish to 0.)

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3 years ago

What is the ordered pair of the solution of the system

Orlov [11]

Answer:

Step-by-step explanation:

5 0

3 years ago

Your grandmother gave you ₱1000 to start a college book fund. She also promised to add another ₱200 each month, if you add ₱50 m

Katena32 [7]

Answer:

A= ₱1000 + t( ₱250) ------where t is the time in months

Step-by-step explanation:

The principal amount ,P, is given as : ₱1000----- P=₱1000 ------equation (i)

Additional amounts to be added by grandmother = ₱200 monthly

Amount expected to add monthly = ₱50

Additional amounts in total added monthly = ₱200 + ₱50=₱250

Monthly amounts ,A, in the fund after the first month, t =1 month will be:

A=P + ₱250= ₱1000 + 1( ₱250) ------where t= 1, amount at end of month 1

A=P +₱250= ₱1000 + 2( ₱250)--------where t=2, amount at end of month 2

A=P +₱250= ₱1000 + 3( ₱250)---------where t=3, amount at end of month 3

A=P +₱250= ₱1000 + 4( ₱250)--------where t=4, amount at end of month 4

From the breakdown above of 4 months, the general equation of monthly amounts will be;

A= ₱1000 + t( ₱250) ------where t is the time in months

8 0

3 years ago

Please help me please

bulgar [2K]

1) p-2
2)10.50
3)$30
4)c+3
5)$15

5 0

3 years ago