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3 years ago

8.75x10^-3 in standard form

Mathematics

1 answer:

Alexeev081 [22]3 years ago

8 0

8.75x0.001=0.00875
that is the number written in standard form

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What is 1.2x=6? And can You show me the work?

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You basiclly divide 6 and 1.2 and get your answer.

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Can someone check if my answer is correct? Thank you!

a_sh-v [17]

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Step-by-step explanation:

you are correct.

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3 years ago

Which ordered pair in the form (a, b) is a solution of this equation?

Evgen [1.6K]

3a - 4b = 21

check (-2 , -3)

3(-2) -4(-3) =21

-6 +12 = 21

6 does not = 21 so NO

check (0 , 7)

3(0) -4(7) =21

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Choice D

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3 years ago

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3 years ago

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Please consider the following values for the variables X and Y. Treat each row as a pair of scores for the variables X and Y (wi

Studentka2010 [4]

Answer:

The Pearson's coefficient of correlation between the is 0.700.

Step-by-step explanation:

The correlation coefficient is a statistical degree that computes the strength of the linear relationship amid the relative movements of the two variables (i.e. dependent and independent).It ranges from -1 to +1.

The formula to compute correlation between two variables <em>X</em> and <em>Y</em> is:

$r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}$

The formula to compute covariance is:

$Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y$

The formula to compute the variances are:

$V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}$

Consider the table attached below.

Compute the covariance as follows:

$Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y$

$=(5\times 165)-(30\times 25)\\=75$

Thus, the covariance is 75.

Compute the variance of X and Y as follows:

$V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\=(5\times 226)-(30)^{2}\\=230\\\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}\\=(5\times 135)-(25)^{2}\\=50$

Compute the correlation coefficient as follows:

$r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}$

$=\frac{75}{\sqrt{230\times 50}}$

$=0.69937\\\approx0.70$

Thus, the Pearson's coefficient of correlation between the is 0.700.

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3 years ago