Answer:
The correct answer is -
A) BbTt x bbTt
B) .5^4 or 1/16 or 0.0625
Explanation:
As it is given that Brachydactylus and PTC tasters both traits are autosomal dominant conditions which mean only one allele would be enough.
For Branchydactylus and For tasting : man and women will be heterogeneous.
Hence,
The Genotype of man = BbTt
The Genotype of wife = bbTt
b. Answer = 0.0625
For Branchydactylus:
Bb X bb
Possible genotypes:
B b
b Bb( Brachydactylus) bb(normal)
b Bb (Brachydactylus) bb (normal)
The probability of a single child being Branchydactylus = 2/4 = 0.5
So, Probability of all 4 child being Branchydactylus = .5 x .5 x .5 x .5 = 0.0625
Answer:
<h2>I think, dead zoning is answer. </h2>
Explanation:
<h2>Hope it helps you.</h2>
The process of meiosis is the cell division that prepares the species for sexual reproduction. Through meiosis cells goes from diploid (2n) cells to haploid (n) gamates. Each daughter cell carries exactly one half of the genetic material from the mother cell. In females the result of meiosis is the production of egg cells, where in the male, the result of meiosis is the production of sperm cells.
