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3 years ago

Find x of the triangle

Mathematics

1 answer:

ANEK [815]3 years ago

5 0

I'm guessing x means the hypotenuse

Use Pythagoras

a^2 + b^2 = c^2

8^ + 15^2 =c^2

64 + 225 = c^2

289 = c^2

c = 17

x = 17

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Luke has 75 Vbucks in his account he spends 5 Vbucks every 2 hours. At this rate how many hours did it take for all 75 V bucks t

mel-nik [20]

Answer:

Step-by-step explanation:

i did the math lol

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2 years ago

Which sign should be used for the following equation? 0.452 _______ 0.712 < > ≤ ≥

ZanzabumX [31]

Answer:

Step-by-step explanation:

0.4<0.7

4 is smaller than 7 so the sighn points to 0.7

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2 years ago

I cannot figure this question out

uysha [10]

Answer:

1/12

Step-by-step explanation:

you need to make sure that they have a common denominator before doing anything.

Find the lowest common multiple (lcm), which would be 12 (3 x 4 = 12)

So then, put 12 as both denominators, and subtract.

7/12 - 9/12 is equal to 28/12 - 27/12, because 3 miltiplied by 4 equals 12, therefore you mutiply the 7 by the 4, and 4 miltiplied by 3 equals 12, therefore you multiply the 9 by the 3.

Sorry if this is confusing, i tried explaining as best i could! Hope this helped!

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3 years ago

Can anyone help me on this

aliya0001 [1]

Answer:

-6 and 1

Step-by-step explanation:

If you separate the different powers (^), you have -m^3 - 5m^3 and -m^2 + 2m^2.

-m^3 - 5m^3 = -6m^3

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3 years ago

The Corporate Lawyer, a magazine for corporate lawyers, reported that out of 200 firms with employee stock ownership plans, 150

tiny-mole [99]

Answer:

The 90% confidence interval for the population proportion of all such firms with this as the primary motivation is (69.96%, 80.04%).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

The Corporate Lawyer, a magazine for corporate lawyers, reported that out of 200 firms with employee stock ownership plans, 150 indicated that the primary reason for setting up the plan was tax related.

This means that $n = 200, \pi = \frac{150}{200} = 0.75$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a p-value of $1 - \frac{0.}{2} = 0.975$ , so $Z = 1.645$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.75 - 1.645\sqrt{\frac{0.75*0.25}{200}} = 0.6996$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.75 + 1.645\sqrt{\frac{0.75*0.25}{200}} = 0.8004$

As percent:

0.6996*100% = 69.96%

0.8004*100% = 80.04%.

The 90% confidence interval for the population proportion of all such firms with this as the primary motivation is (69.96%, 80.04%).

6 0

3 years ago