Solution :
We have to provide an expression for the binary numbers. There can be binary fractions or integers. Whenever there is leading 0, it is not allowed unless the integer part is a 0.
Thus the expression is :
![$(\in +.(0+1)^*(0+1))+(0.(0+1)^*(0+1))]$](https://tex.z-dn.net/?f=%24%28%5Cin%20%2B.%280%2B1%29%5E%2A%280%2B1%29%29%2B%280.%280%2B1%29%5E%2A%280%2B1%29%29%5D%24)
Answer:
monye
Explanation:
cash or credit becuse with what else are they gonna pay with
The answer is B. Issue report cards of grades.
Answer:
Options A and C.
Explanation:
In Oracle Cloud Infrastructure the two options which allows you to increase disk performance are;
1. Terminate the compute instance preserving the boot volume. Create a new compute instance using a VM Dense IO shape using the boot volume preserved.
2. Create a backup of the boot volume. Create a new compute instance a VM Dense IO shape and restore the backup.
Answer:
getline(cin, address);
Explanation:
Given
String object: address
Required
Statement that reads the entire line
The list of given options shows that the programming language is c++.
Analysing each option (a) to (e):
a. cin<<address;
The above instruction will read the string object until the first blank space.
Take for instance:
The user supplied "Lagos state" as input, only "Lagos" will be saved in address using this option.
b. cin address:
This is an incorrect syntax
c. getline(cin,address);
Using the same instance as (a) above, this reads the complete line and "Lagos state" will be saved in variable address
d. cin.get(address);
address is created as a string object and the above instruction will only work for character pointers (i.e. char*)
<em>From the above analysis, option (c) is correct.</em>